Answer:
C)T
Explanation:
The period of a mass-spring system is:
As can be seen, the period of this simple harmonic motion, does not depend at all on the gravitational acceleration (g), neither the mass nor the spring constant depends on this value.
Answer:
Acceleration is 
Solution:
As per the question:
Radius of the circle, R = 1.8 m
Height above the ground, h = 1.8 m
Horizontal distance, x = 9.9 m
Now,
The magnitude of the centripetal acceleration can be calculated as:
where
v = velocity
R = radius
= centripetal acceleration
Now, if we consider the vertical component of motion only, then considering the initial velocity, 'u' = 0, from kinematic eqn:
t = 0.606 s
Now, for the horizontal component of velocity:
x = vt
Now, we know that the centripetal acceleration is given by:
Complicated 2-step process.
<span>1. Write down the formula for "frequency of a pendulum" from your textbook. </span>
<span>f = (1/2pi) * sqrt(g/L) </span>
<span>2. Plug in g and L.
I hope this can help!</span>
Answer:
3.75 m/s
Explanation:
Given that a bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude 0.50 m/s^2. After 2.0 s the bee is moving to the right with a speed of 2.75 m/ s
What was the velocity of the bumblebee right before the breeze?
Since the breeze blows with the acceleration of 0.5 m/s^2 for 2 seconds, we can calculate the magnitude of the velocity at which it moves.
Acceleration = velocity/ time
Substitute the acceleration and time into the formula
0.5 = V/2
Cross multiply
V = 2 × 0.5
V = 1 m/s
The bumblebee is travelling right ward while the wind travels leftward.
The relative velocity = 2.75 m/s
Let the bumblebee speed = Vb
While the wind = VW
Vb - Vw = 2.75
Substitute the wind speed into the formula
Vb - 1 = 2.75
Vb = 2.75 + 1
Vb = 3.75 m/s
Therefore, the velocity of the bumblebee right before the breeze is 3.75 m/s
<span>The magnitude of the gravitational force between two bodies is the product of their masses divided by the square of the distance between them. So we have F = M1*M2 / r^2. M1 = 7.503 * 10e24 and M2 = 2.703 * 10e22 and r= 2.803 * 10e8; r^2 = 5.606 *10e16. So we have 7.503 *2.703 *10^(24+22) = 20.280 * 10^(46). Then we divide our answer by 5.606 * 10e16 which is the distance ; then we have 3.6175 * 10 e (46- 16) = 3.6175 * 10e30.
To find the acceleration we use Newton's second law F = ma. F is 3.6175 * 10e30 and M is 7.503 * 10e24 so a = F/M and then we have 3.6175/7.503 * 10e (30-24) = 0.48 * 10e6.
Similarly for moon, we have a = 3.6715/2.703 * 10e(30-22). = 1.358 * 10e8</span>
