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hram777 [196]
2 years ago
10

A food web is

Chemistry
1 answer:
Allushta [10]2 years ago
8 0
A food web is a graphic representation of all possible energy pathways through an ecosystem.
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During which of the following phases of the moon do we see the left half of the moon as lit?
xxMikexx [17]
During the 3rd quarter
7 0
2 years ago
Anhydrous CoCl2 is blue; CoCl2•6H2O is red. When CoCl2•6H2O is heated and water is clearly being driven off, it becomes uniforml
Sedaia [141]

Answer: On losing 6 moles of water, cobalt chloride forms unstable violet-coloured ions, before generating its stable blue-coloured anhydrous form.

Explanation:

The hydrated cobalt chloride loses its 6 water of crystallization, then dissociates into ions: cobalt ions and chlorine ions that appear violet, and quickly combined to form the stable anhydrous Cobalt chloride with blue colour.

4 0
3 years ago
the radius of magnesium atom is 0.160nm. the radius of a magnesium ion is 7.2x 10^-11m. explain the difference in size between t
Allushta [10]

Answer:

during reaction magnesium lises ions.

Explanation:

magnesium reacts by losing two ions which makes it smaller in size.

8 0
2 years ago
When 3.0 kg of water is warmed from 10 °C to 80 °C, how much heat energy is needed?
Naddik [55]

Answer:

THE HEAT NEEDED TO CHANGE 3KG OF WATER FROM 10 C TO 80 C IS 877.8kJ OR 877,800 J.

Explanation:

Mass = 3.0 kg = 3 * 1000 = 3000 g

Initial temperature = 10 C

Final temperature = 80 C

Change in temperature = 80 - 10 = 70 C

Specific heat of water = 4.18 J/g C

Heat needed = unknown

Heat is the amount of energy in joules needed to change a gram of water by 1 C.

Heat = mass * specific heat * change in temperature

Heat = 3000 g * 4.18 J/g C * 70 C

Heat = 877 800 Joules

Heat = 877.8 kJ.

The heat needed to change 3 kg mass of water from 10 C to 80 C is 877,800 J or 877.8 kJ.

6 0
3 years ago
A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg
Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a\sqrt{3}/4

Given

a = 360 pm

Therefore

r = r = radius = 360\sqrt{3}/4= 155.88 pm

Or

156 pm

3 0
3 years ago
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