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sergejj [24]
3 years ago
8

Which statements describe codominance? Select three options.

Chemistry
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

Which statements describe codominance? Select three options.

✖Traits are usually dominant.

✔Traits are neither dominant nor recessive.

✖Offspring exhibit an intermediate form of alleles from the parents.

✔Both alleles, one from each parent, are expressed in offspring.

✔Codominance involves the interaction of two alleles.

I did the test on edge, hope this helped. brianliest would be appreciated.

solong [7]3 years ago
4 0

  • Traits are neither dominant nor recessive.

  • Both alleles, one from each parent, are expressed in offspring.

  • Codominance involves the interaction of two alleles.

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When an electron in an atom spontaneously jumps from a higher energy state to a lower energy state, the atom?
vlabodo [156]
If an atom suffers from a collision, that causes an electron to jump from a lower to higher state, it is called collisional excitation 
6 0
2 years ago
If 100.0 grams of na3n decompose to form sodium and nitrogen, how many moles of sodium are formed? write and balance equation be
Yakvenalex [24]
The balanced equation is:
2Na_3N-\ \textgreater \ 6Na + N_2

Then proceed with the following equations.


100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa

The answer is 83.12gNa.
7 0
3 years ago
Read 2 more answers
At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
2 years ago
An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
zheka24 [161]

Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

Option A: negative, positive

Option B: negative, negative

Option C: positive, positive

Option D: positive, negative

Answer:

Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

ΔG = ΔH - TΔS

free energy is the energy available to do work. Thus, if a particular reaction is accompanied by a release of usable energy (that is, <u>ΔG is negative</u><u>), it is said to be</u><u> exergonic</u>. On the other hand, if a reaction consumes energy (that is, <u>ΔG is positive</u><u>), it is said to be </u><u>endergonic</u>.

Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

ΔG = ΔH - TΔS

           -        -

This means that the reaction proceeds spontaneously at low temperatures. At high temperatures, the reverse reaction becomes spontaneous. An example of that would be the following reaction:

NH₃(g) + HCl(g) → NH₄Cl(s)

4 0
3 years ago
Please help me ASAP
blondinia [14]

Answer:

weak acid

Explanation:

pH scale is from 0 to 14

pH =7 is for water which is neutral.  it is neither acidic or basic as the hydrogen ion concentration is equal to hydroxyl ion concentration.

Lesser the pH value than 7 greater the acidic nature. And greater the pH value  than 7 more the basic nature.

Given pH=3-7 So the indicated interval represents weakly acidic.

4 0
2 years ago
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