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JulijaS [17]
3 years ago
10

Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of Pb and H+ in the bal

anced reaction?
Pb2+(aq) + NH+4(aq) --> Pb(s) + NO-3(aq)
Chemistry
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

kujgedyjmnyged\jmngv\gedkjmyten

Explanation:

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A student determines the aluminum content of a solution by first precipitating it as aluminum hydroxide, and then decomposing th
Vladimir [108]

Answer: The student should obtain <u>1.103 g of aluminum oxide </u>

Explanation:

  • First we write down the equations that represent the aluminum hydroxide precipitation  from the reaction between the aluminum nitrate and the sodium hydroxide:

Al(NO3)3 + 3NaOH → 3NaNO3 + Al(OH)3

Now,  the equation that represents the decomposition of the hydroxide to aluminum oxide by heating it.

2Al(OH)3 → Al2O3 + 3H2O

  • Second, we gather the information what we are going to use in our calculations.

Volumen of  Al(NO3)3 = 40mL

Molar concentration of Al(NO3)3 =  0.541M

Molecular Weight Al2O3 = 101.96 g/mol

  • Third, we start using the molar concentration of the aluminum nitrate and volume used to find out the total amount of moles that are reacting

\frac{0.541moles Al(NO3)3}{1L} x\frac{1L}{1000mL} x 40mL Al(NO3)3 =  0.022moles Al(NO3)3

then we use the molar coefficients from the  equations to discover the amount of Al2O3  moles produced

0.022moles Al(NO3)3 x \frac{1mol Al(OH)3}{1mol Al(NO3)3} X\frac{1mol Al2O3}{2molAl(OH)3} = 0.011 moles Al2O3

finally, we use the molecular weight of the Al2O3  to calculate the final mass produced.

0.011moles Al2O3 x \frac{101.96g Al2O3}{1mol Al2O3} = 1.103g Al2O3

4 0
4 years ago
Which of the following requires the most input of energy? A) Melting a substance B) Raising the temperature by 1 degrees c C) De
Butoxors [25]

Answer:

The correct answer is D Vaporizing a substance.

6 0
3 years ago
Describe what happens to the molecules in the ice as temperature of the ice increases
german

Answer:

When you heat ice, the individual molecules gain kinetic energy, but until the temperature reaches the melting point, they don't have energy to break the bonds that hold them in a crystal structure. They vibrate more quickly within their confines as you add heat, and the temperature of the ice goes up.

8 0
3 years ago
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The alternating rising and falling of the sea caused by the gravitational pull of the moon is called?​
Mashcka [7]

Answer: Tides are the regular, alternating rise and fall of sea level caused by the gravitational pull of the moon and sun. The changing of the tide is often rapid and dramatic. On a smaller scale, similar motions occur on large lakes, in the atmosphere, and even within the solid earth.

Explanation: can I please have brainliest?

8 0
3 years ago
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Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react
Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of BCl_3 = 60 g

Mass of H_2O = 37.5 g

Molar mass of BCl_3 = 117 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of HCl = 36.5 g/mole

First we have to calculate the moles of BCl_3 and H_2O.

\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)

From the balanced reaction we conclude that

As, 1 mole of BCl_3 react with 3 mole of H_2O

So, 0.513 moles of BCl_3 react with 3\times 0.513=1.539 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and BCl_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of HCl.

As, 1 mole of BCl_3 react to give 3 moles of HCl

So, 0.513 moles of BCl_3 react to give 3\times 0.513=1.539 moles of HCl

Now we have to calculate the mass of HCl.

\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl

\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0
3 years ago
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