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vagabundo [1.1K]
4 years ago
6

Where is the carbon in a temperate

Chemistry
1 answer:
tangare [24]4 years ago
8 0

In the high temperate

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Determine the pH of a 0.530 M solution of carbonic acid that has an acid dissociation constant of 4.4 x
Veronika [31]

Answer:

Explanation:

H2CO3  =  H+   +  HCO3-   H2CO3  =  0.530 M  Ka =4.4 X10^-7

Ka =[H+][A-]/[HA]        [H+] = [A-]

0.530 M x 4.4 X10^-7=  [H+}^2

2.32 X10^-7  =  [H+}^2

23.2 X10^-8 = [H+}^2

4.83 X 10^-4 = [H+]

pH = - log 4.83 X 10^-4

pH = -(.68-4)

pH =-(-3.32)

pH= 3.32

5 0
3 years ago
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Como se representan los elementos en la tabla¿?
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Answer:

Na sodiops los elementos químicos se representan como el átomo, el núcleo, donde se necuentran los protones y neutrones van dentro, los electrones afuera, girando de forma elíptica alrededor del núcleo. ... por ejemplo el oxígeno numero atómico 8, tiene 8 protones y 8 electrones. el número de neutrones es diferente.

Explanation:

4 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
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Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

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We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

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1 year ago
Which two types of clouds indicate fair weather
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Cirrus and cumulus indicate fair weather
5 0
4 years ago
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If calcium were to react with carbon, what would likely form?
Lady_Fox [76]

Answer: calcium oxide will react with carbon dioxide to form calcium carbonate. I don't know if that's what you were asking.

Explanation:

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