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Alchen [17]
2 years ago
6

Which is not expecting acceleration?

Physics
2 answers:
TiliK225 [7]2 years ago
7 0

#1)

1).  A point on the outside of a spinning top whose rotational speed is constant.

It will not accelerate as its net speed is ZERO

2).  A skydiver whose air resistance is equal to that of her weight.

Since weight is counterbalanced by resistance so here net force is zero so acceleration must be zero here

3).   A car on the freeway experiencing a net force of -120 N.

Since there it acts net force F = -120 N so it will accelerate here

4).  A submerged beach ball whose buoyant force is eight times the force of gravity on it.

Since buoyant force is more than weight of the ball so it will accelerate upwards

#2)

A non accelerating fra me is always a valid inertial frame

A frictionless spinning merry go round.

(since it is having centripetal acceleration so it is non inertial frame)

A falling rock.

(Since it is falling with acceleration a = 9.8 m/s^2 so it is non inertial)

A hot air balloon moving at 30 degrees east of north with no net force.

(Since net force on hot air balloon is ZERO so it is Inertial Frame)

A space shuttle whose boosters just ignited for takeoff.

(Since space shuttle ignite the boosters so it will accelerate here and hence it is non inertial)

#3

here two forces given as

F_1 = 4320 N towards right

F_2 = 4380 N towards Left

Since left side applied force is more than right side applied force so net force on it will be towards Left and it is given by

F = 4380 - 4320 = 60 N

So it is 60 N Left

Mnenie [13.5K]2 years ago
4 0

Answer:

1. A submerged beach ball whose buoyant force is eight times the force of gravity on it.

2. A hot air balloon moving at 30 degrees east of north with no net force.

3. 60 N to the left

Explanation:

1. A submerged ball is not expecting any form of acceleration. This is because there is no form of motion on it. The only forces that are experienced on the ball are the compressing forces from the water.

2. A hot air balloon will be a good point of reference. This is because it has no definite direction of movement or acceleration.

3. The sum of the forces will be:

3280 - 3220 = 60

so the resultant force will be 60 N to the left.

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An apple is placed 20.0 cm in front of a diverging lens of focal length 10.0 cm. Find the image distance and the magnification o
jenyasd209 [6]

Answer:

Image distance of apple=-6.7 cm

Magnification of apple=0.33

Explanation:

We are given that an apple is placed 20.cm in front of a diverging lens.

Object distance=u=-20 cm

Focal length=f=-10 cm

Because focal length of diverging lens is negative.

We have to find the image distance and magnification of the apple.

Lens formula

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

Substitute the values then we get

-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}

\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}

\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}

v=-\frac{20}{3}=-6.7 cm

Image distance of apple=-6.7 cm

Magnification=m=\frac{v}{u}=\frac{-\frac{20}{3}}{-20}

Magnification of apple=\frac{1}{3}=0.33

Hence, the magnification of apple=0.33

5 0
2 years ago
PLEASE ANSWER, I NEED HELP
Scorpion4ik [409]

1) The gravitational force between Ellen and the moon is 1.56\cdot 10^{-3} N

2) The two forces are equal, while the acceleration of the bus is smaller than the acceleration of the bicycle.

Explanation:

1)

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 47 kg is the mass of Ellen

m_2 = 7.35\cdot 10^{22} kg is the mass of the moon

r=3.84\cdot 10^8 m is the distance between Ellen and the moon

Substituting, we find the gravitational force between Ellen and the moon:

F=(6.67\cdot 10^{-11})\frac{(47)(7.35\cdot 10^{22})}{(3.84\cdot 10^8)^2}=1.56\cdot 10^{-3} N

2)

We can analyze the forces acting in the collision between the bus and the bicycle by using Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

Applied to our problem, this means that the force exerted by the bus on the bicycle during the collision (action force) is equal (and opposite) to the force exerted by the bicycle on the bus (reaction force).

Now let's analyze the accelerations of the two vehicles. We can find the acceleration of each vehicle by using Newton's second law:

a=\frac{F}{m}

where

a is the acceleration

F is the force exerted on the vehicle

m is the mass of the vehicle

As we said previously, the force F exerted on each of the two vehicles: so, the acceleration only depends on the mass. In particular, the acceleration is inversely proportional to the mass: therefore, the larger the mass of the vehicle, the smaller the acceleration. This means that the acceleration of the bus is smaller than the acceleration of the bicycle.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

And about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

6 0
3 years ago
What two bodily functions are increased by a warm up
drek231 [11]

1) Blood flow: increases during warming improving muscle and joint elasticity. This decreases the possibility of having an injury.


2) Body temperature: This causes the cellular metabolism to increase. It also causes vasodilatation that allows a greater supply of oxygen and nutrients.

6 0
2 years ago
PLEASE PROVIDE AN EXPLANATION.<br><br> THANKS!!!
ziro4ka [17]

Answer:

(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz

(b) 250 m/s

(c) 1250 N

(d) Positive x-direction

(e) 6.00 m/s

(f) 0.0365 m

Explanation:

(a) The standard form of the wave is:

y = A cos ((2πf) t ± (2π/λ) x)

where A is the amplitude, f is the frequency, and λ is the wavelength.

If the x term has a positive coefficient, the wave moves to the left.

If the x term has a negative coefficient, the wave moves to the right.

Therefore:

A = 0.0800 m

2π/λ = 0.300 m⁻¹

λ = 20.9 m

2πf = 75.0 rad/s

f = 11.9 Hz

(b) Velocity is wavelength times frequency.

v = λf

v = (20.9 m) (11.9 Hz)

v = 250 m/s

(c) The tension is:

T = v²ρ

where ρ is the mass per unit length.

T = (250 m/s)² (0.0200 kg/m)

T = 1250 N

(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).

(e) The maximum transverse speed is Aω.

(0.0800 m) (75.0 rad/s)

6.00 m/s

(f) Plug in the values and find y.

y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))

y = 0.0365 m

8 0
2 years ago
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How many protons are in this atom if it has a balanced charge
Lerok [7]
It would be 20 protons left because 1-19= 20
7 0
2 years ago
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