Answer:
#1 and #2 are the correct answers.
Explanation: The equation isn’t balanced because the amount of hydrogen and nitrogen in the reactants doesn’t match the amount of hydrogen and nitrogen in the products. When the coefficients are all set to 1, there are two nitrogen atoms in the reactants but only one in the products. Similarly, there are two hydrogen atoms in the reactants, but three in the products.
First, we have to get the theoretical yield of CaO:
the balanced equation for the reaction is:
CaCO3(s)→CaO(s) +CO2(g)
covert mass to moles:
moles CaCO3 = mass of CaCO3 / molar mass of CaCO3
= 2x10^3 /100 = 20 moles
the molar ratio between CaCO3 : CaO = 1:1
∴moles of CaO = 1* 20 = 20 moles
∴mass of CaO = moles of CaO * molar mass of CaO
= 20 * 56 = 1120 g
∴the theoritical yield = 1120 g and we have the actual yield =1.05X10^3
∴Percent yield = actual yield / theoritical yield *100
= (1.05x10^3) / 1120 * 100
= 94 %
The fourth most abundant element in terms of mass is Carbon.
The first, second, and third most abundant element in terms of mass are Hydrogen, Helium, and Oxygen, respectively.
Hope this helps~
Answer:
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Explanation:
Answer:
CHOOH (aq) + H₂O (l) ⇄ HCOO⁻ (aq) + H₃O⁺ (aq)
Weak acid Base Conj. strong base Conj. acid
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
Weak acid Weak Base Conj. strong acid Conj. strong base
Explanation:
To determine the acid-base pairs in the example below we follow the Brownsted Lowry theory.
An acid releases protons
A base accepts protons
CHOOH (aq) + H₂O (l) ↔ HCOO⁻ (aq) + H₃O⁺ (aq)
Formic reacts to water in order to produce formate and hydroniums
Formic release a proton → Acid
Formate can accepted the proton → Conjugate base
Water will be the base, because it will acepted the proton, so the hydronium will be the conjugate acid, because it will release the proton to become water again.
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
The sulfidric behaves as an acid, it release the proton to ammonia.
The acid sulfide, becomes the base. It can accept the proton for being, H₂S again.
Then the ammonia is the base (it can accept H⁺) and the ammonium is the conjugate acid (it release the H⁺)