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BigorU [14]
3 years ago
10

The tension in the cable is 100N find the mass of the ball

Physics
1 answer:
zaharov [31]3 years ago
7 0

The correct answer of this question is : 10.2 Kg.

EXPLANATION :

As per the question, the ball is attached to the cable.

The tension produced in the cable when the ball is hanged from it, is equal to the weight of the ball. It is so because the cable maintains its equilibrium.

Hence, tension in the cable = weight of the ball.

The tension produced in the cable is given as T = 100 N.

The weight of the ball is equal to the product of mass with acceleration due to gravity.

Let the mass  of the ball is m.

Hence, weight of the ball W = mg

Here, g is known as acceleration due to gravity, and its value is g = 9.8\ m/s^2.

From above, we know that W = T

                                           ⇒ mg = 100 N

                                           ⇒ m = \frac{100}{g} Kg

                                                    = \frac{100}{9.8}\ Kg

                                                    = 10.2 Kg.              [ans]

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The field used in the Canadian football League (CFL) has the midfield marker at the 55 yard line.how long is the fiend from goal
kogti [31]

Answer:

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Explanation:

Well if 55 yards is 1/2 of the field then 2 x 55 = 110 yards is total field length

3 0
2 years ago
Salt is now added to the water in the bucket, increasing the density of the liquid. what happens to the tension in the string ?
AlexFokin [52]

The question involves a ping-pong ball that is held submerged in a bucket by a string attached to the bottom of the bucket.

The answer is the tension of the string will increase. This is because making the water salty increases its density, and consequently, increases its buoyancy. This is why sea water is more buoyant than fresh water. Therefore the ping pong is pushed more upwards by the water when salt is added than initially. This gives the string more tension.


5 0
3 years ago
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.4cm apart with a 28kV potential d
yulyashka [42]

Answer:

a)   F = 3.2 10⁻¹⁰ N , b)       v = 9.9 10⁷ m / s

Explanation:

a) The electric force is

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The electric field is related to the potential reference

     V = E d

     E = V / d

Let's replace

    F = e V / d

Let's calculate

    F = 1.6 10⁻¹⁹ 28 10³ / 1.4 10⁻²

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b) For this part we can use kinematics

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Acceleration can be found with Newton's second law

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Let's calculate the speed

       v = √ (2 3,516 10¹⁷ 1.4 10⁻²)

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Initial force, f =100 lbf

Compression, x = 1 in

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