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Step2247 [10]
3 years ago
11

Chris is about to do an experiment​

Physics
2 answers:
Shkiper50 [21]3 years ago
7 0

Answer:

Epic I guess

Explanation:

Arada [10]3 years ago
4 0

Answer:

Cool tell me about it

Explanation:

/*/

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When you push a 1.90-kg book resting on a tabletop, you have to exert a force of 2.10 N to start the book sliding. Once it is sl
zimovet [89]
Static frictional force = ƒs = (Cs) • (Fɴ)
              2.26 = (Cs) • m • g
              2.26 = (Cs) • (1.85) • (9.8)
           Cs = 0.125 
kinetic frictional force = ƒκ = (Cκ) • (Fɴ)
              1.49 = (Cκ) • m • g
              1.49 = (Cκ) • (1.85) • (9.8)
           Cκ = 0.0822 
3 0
3 years ago
A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determi
KatRina [158]

Answer:

Explanation is given

Mark Me as Branliest

3 0
3 years ago
A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
3 years ago
How many protons would the element with the atomic number 10 contain?
galben [10]
The atomic number is the same as the proton number so the answer would be D) 10
3 0
3 years ago
⚠️ PLEASE HELP ⚠️
Svetllana [295]

Answer:

-79.6

-80

-81.2

Explanation:

5 0
3 years ago
Read 2 more answers
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