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3 years ago

12

In an intermittent weld, what is the distance between the end of one weld and the beginning of the next, if the length and pitch

dimensions are 4-10?

1 answer:

zlopas [31]3 years ago

7 0

Answer:

jjwjwvenfifgbsieeeww wet

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A product whose total work content time = 50 min is assembled on a manual production line at a rate of 24 units per hour. From p

valentinak56 [21]

Answer:

a)Cycle time = 2.37 min

b)Numbers of workers =21

c)Stations on the line =24

Explanation:

Given that

Total work content time(TWC) = 50 min

Production rate Rp= 24 units/hr

manning level will be close =1.5

Line balancing efficiency =0.94

a)

Cycle time

$T_c=\dfrac{60E}{R_P}$

$T_c=\dfrac{60\times 0.95}{24}$

Cycle time = 2.37 min

b)

Numbers of workers ,W

$W=\dfrac{TWC}{T_c}$

$W=\dfrac{50}{2.37}$

W= 21

Numbers of workers =21

c)

Stations on the line(n)

Lets find service time Ts

Ts = Cycle time - Time for repositioning

Ts = Tc- Tr

Ts= 2.37 - 9/ 60 min

Ts= 2.22 min

We know that efficiency

$\eta=\dfrac{TWC}{n.T_s}$

$0.94=\dfrac{50}{n\times 2.22}$

n=23.94 ⇒n=24

n=24

Stations on the line =24

7 0

3 years ago

A specimen has circular cross-sectional area with initial diameter d = 26 mm and a gauge length Lo = 200 mm. A force P = 127 kN

steposvetlana [31]

The ahahte ekiebecwkwlwtfe einshgeh dinzgdwbsine ensue d

4 0

3 years ago

A binary star system consists of two stars of masses m1m1m_1 and m2m2m_2. The stars, which gravitationally attract each other, r

d1i1m1o1n [39]

Answer:

$a_c_2=\dfrac{a_c_1\times m_1}{m_2}$

Explanation:

The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>

The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

$a_c=\dfrac{F_c}{m}$

Thus, you can write the equations for each star:

$a_c_1=\dfrac{F_c_1}{m_1}$

$a_c_2=\dfrac{F_c_2}{m_2}$

As per Newton's third law, the centripetal forces are equal in magnitude. Then:

$a_c_1\times m_1=a_c_2\times m_2$

Now you can clear $a_c_2$ :

$a_c_2=\dfrac{a_c_1\times m_1}{m_2}$

6 0

4 years ago

An electronic toy is powered by three 1.58-V alkaline cells, each with an internal resistance of 0.0205 Ω, and a 1.53-V carbon-z

mina [271]

Answer:

(a) The current in amperes that flows through the toy's circuit is 0.923A

(b) The power supplied to the toy is 5.78721W

(c) The internal resistance r2 of the failed dry cell is 72Ω

Explanation:

From the circuit diagram attached. We have the electric component:

B1 = 3* 1.58 = 4.74V

B2 = 1.53V

r1 = 3*0.0205 = 0.0615Ω

r2 = 0.105Ω

R = 6.625Ω

Since the internal resistances and the resistor R are connected in series, we can calculate the total resistance RT as

RT = r1 + r2 +R = 0.0615 + 0.105 + 6.625

= 6.7915Ω

Total Voltage supplied to the circuit by both batteries V = B1 + B2 = 4.74 + 1.53 = 6.27V

(a) CIRCUIT CURRENT

The current I, flowing through the circuit is i = $\frac{V}{R_{T}}$ = $\frac{6.27}{6.7915}$ =0.923A

The current in amperes that flows through the toy's circuit is 0.923A

(b) THE POWER SUPPLIED TO THE TOY

Power P = I*V =0.923*6.27 = 5.78721W

The power supplied to the toy is 5.78721W

(c) THE VALUE OF r2

Due to dry cell failure, the power supplied to the toy is reduced to 0.5W

Now Power P = $\frac{V^{2} }{R}$ . To calculate the new total resistance of the circuit we will make R the subject of the formular

R= $\frac{V^{2} }{P}$ = $\frac{6.27^{2} }{0.5}$ = $\frac{39.3129}{0.5}$ = 78.6258Ω

Remember that RT = r1 + r2 + R

r1 =RT- (R +r2)

r1 = 78.6258 - 6.6865 =71.9393Ω

The internal resistance r2 of the failed dry cell is 72Ω

6 0

3 years ago

Read 2 more answers

You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then

Contact [7]

Answer:

let number = 0

while number < 1

begin

print "Enter a positive integer: "

read number

end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

to an integer value

while currentFactor <= lastFactor

begin

if number is evenly divisible by currentFactor

begin

print currentFactor

let number = number / currentFactor

end

else

let currentFactor = currentFactor + 1

end_if

end

end_while

print a message if number is prime:

if prime == TRUE

print "Your number is prime"

end_if

Explanation:

4 0

3 years ago