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sasho [114]
4 years ago
7

Which one of the following types of gas is flammable? a. Neon b. Peroxide. c. Acetylene d. Carbon Dioxide ​

Engineering
2 answers:
kvasek [131]4 years ago
8 0

Answer:

C: Acetylene

Explanation:

Used as a fuel for gas torches

Delvig [45]4 years ago
3 0

Answer:

D Carbon Dioxide

Explanation:

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What is the locating position of the land field?​
Ivahew [28]

Any point on earth can be located by specifying its latitude and longitude, including Washington, DC, which is pictured here. Lines of latitude and longitude form an imaginary global grid system, shown in Fig. 1.17. Any point on the globe can be located exactly by specifying its latitude and longitude.

4 0
3 years ago
The question “How do plants convert sunlight to energy?” best represents which of the following?
OverLord2011 [107]

Answer:

D

Explanation:

I would say this awnser because its the only one that makes sence to me

5 0
3 years ago
A 0.2-m^3 rigid tank equipped with a pressure regulator contains steam at 2MPa and 320C. The steam in the tank is now heated. Th
prohojiy [21]

Answer:

Q=486.49 KJ/kg

Explanation:

Given that

V= 0.2 m³

At initial condition

P= 2 MPa

T=320 °C

Final condition

P= 2 MPa

T=540°C

From steam table

At P= 2 MPa and T=320 °C

h₁=3070.15 KJ/kg

At P= 2 MPa and T=540°C

h₂=3556.64  KJ/kg

So the heat transfer ,Q=h₂ - h₁

Q= 3556.64 - 3070.15  KJ/kg

Q=486.49 KJ/kg

7 0
3 years ago
RC4 has a secret internal state which is a permutation of all the possible values of the vector S and the two indices i and j.
Stolb23 [73]

Answer:

a. Using a straight forward scheme, the RC4 algorithm stores 2064 bits in the interval state.

b. 1700 bits

Explanation:

See RC4 Algorithm attached with details

3 0
3 years ago
A basketball has a 300-mm outer diameter and a 3-mm wall thickness. Determine the normal stress in the wall when the basketball
faltersainse [42]

Answer:

2.65 MPa

Explanation:

To find the normal stress (σ) in the wall of the basketball we need to use the following equation:

\sigma = \frac{p*r}{2t}

<u>Where:</u>

p: is the gage pressure = 108 kPa

r: is the inner radius of the ball

t: is the thickness = 3 mm  

Hence, we need to find r, as follows:

r_{inner} = r_{outer} - t    

r_{inner} = \frac{d}{2} - t

<u>Where:</u>

d: is the outer diameter = 300 mm

r_{inner} = \frac{300 mm}{2} - 3 mm = 147 mm

Now, we can find the normal stress (σ) in the wall of the basketball:

\sigma = \frac{p*r}{2t} = \frac{108 kPa*147 mm}{2*3 mm} = 2646 kPa = 2.65 MPa

Therefore, the normal stress is 2.65 MPa.

I hope it helps you!

3 0
3 years ago
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