3 years ago

A weightlifter lifts a 1,250 N barbell 2 m in 3 s. How much power was used to lift the barbell?

1 answer:

5 0

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ElenaW [278]

Explanation:

The given data is as follows.

Speed of the bullet (v) = 500 m/s

Distance during one RC time constant (d) = 1 mm = $1 \times 10^{-3} m$

Capacitance (C) = 600 $\mu F$ = $600 \times 10^{-6} F$

Hence, formula for speed of the bullet is as follows.

v = $\frac{d}{t}$

or, t = $\frac{d}{v}$

Time constant for RC circuit is as follows.

t = RC

R = $\frac{t}{C}$

= $\frac{d}{vC}$

= $\frac{1 \times 10^{-3}}{500 \times 600 \times 10^{-6}}$

= $3.33 \times 10^{-3} ohm$

Thus, we can conclude that resistance in the flash tube is $3.33 \times 10^{-3} ohm$ .

3 0

3 years ago

Klio2033 [76]

heat and pressure would be your answer hope it helps

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eimsori [14]

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notka56 [123]

F=ma
50=m(5)
m=10kg
hence,ans is B

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3 years ago

wlad13 [49]

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4 years ago