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Feliz [49]
3 years ago
11

Mei wants to study whether heart rate increases more during certain exercises than during others. She designs an experiment to t

est the heart rates of classmates in the morning and in the evening for three days, immediately after doing jumping jacks, doing push-ups, or running in place. What is the dependent variable in this experiment?
Chemistry
2 answers:
baherus [9]3 years ago
8 0

The change in heart rate is the dependent variable.

postnew [5]3 years ago
7 0
The differing heart rates is the dependent variable. This is because it is dependent on the exercise that will depict the heart rate
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Approximately 30% of the earth’s fresh water is stored in– A lakes. B streams. C groundwater. D living things.
kirill115 [55]
C ground water hope this is helpful
7 0
3 years ago
What volume of 1.5M NaOH is needed to provide 0.75 mol of NaOH?
lutik1710 [3]
1.5M NaOH so we've 1.5 moles of NaOH in 1L of solution

1L = 1000 ml

1.5 moles of NaOH ------------in------------- 1000 ml
0.75 moles of NaOH ----------in---------------x ml
x = 500 ml

<em><u>answer: C</u></em>
5 0
3 years ago
(-5)+(+7)-(-4) + (+12)<br>A 8<br>B 10<br>C 18<br>d 20<br>​
Vladimir79 [104]

Answer:

C-18

Explanation:

Step one follow order of operations

Add and subtract from left to right(-5)+(7)=2-(-4)+(12)

STEP 2

Apply negative Rule -(-4)=+4=2+4+(12)

then add 2+4+12=18

5 0
3 years ago
1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.
Anarel [89]

<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of carbon dioxide = 1 lb = 453.6 g   (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm   (Conversion factor:  1 psia = 0.068 atm)

V = Volume of carbon dioxide = 0.6ft^3=16.992L    (Conversion factor:  1ft^3=28.32L )

n = number of moles of carbon dioxide = 10.31 mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the system = ?

Putting values in above equation, we get:

13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K

Hence, the temperature of the system is 273 K

8 0
3 years ago
If a solution containing A+ ions and a solution containing B- ions have just been mixed and [A+][B-] is greater than Ksp of AB,
frozen [14]

Answer:

Explanation:

In the solution of AB , they are split  to give ions as follows

AB ⇄ A⁺ + B⁻

Product of concentration of A⁺ and B⁻ in saturated solution of AB is constant .

This is called Ksp

Ksp = [A⁺] [ B⁻]

If product of concentration of A⁺  and B⁻ exceeds Ksp , the equilibrium shifts to the left side and excess ions come out of solution in the form of precipitate. So second option is the answer.

4 0
3 years ago
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