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algol [13]
3 years ago
6

An ultra-low friction pulley deal is as shown. The two weights experience an acceleration of 3.8m/s2. The first weight has 1.08k

g. Find the mass of the second weight
Physics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

The mass of the second weight is approximately 0.477 kg

Explanation:

The given parameters are;

The acceleration experienced by the two weights = 3.8 m/s²

The mass of the first weight = 1.08 kg

The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;

a = \dfrac{g \cdot (M - m)}{M + m}

Where;

a = The common acceleration of the two weights

g = The acceleration due to gravity = 9.81 m/s²

M = The mass of the first weight = 1.08 kg

m = The mass of the second weight

Therefore, we have;

m = \dfrac{M\cdot (g -a )}{g + a} = \dfrac{1.08\times (9.81 -3.8 )}{9.81 + 3.8} \approx 0.477

The mass of the second weight = m ≈ 0.477 kg

The mass of the second weight ≈ 0.477 kg.

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