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Zigmanuir [339]
3 years ago
11

Al + h2so4 → al2(so4)3 + h2 when the equation is correctly balanced, the coefficient of h2so4 is -

Chemistry
1 answer:
Yuri [45]3 years ago
8 0
First, we have to balance the equation:

Al +  H2SO4 → Al2(SO4)3 + H2

we have the number of Al atoms not equal on both sides so we will put 2 Al instead of Al on the left side of the equation.

2Al + H2SO4  → Al2(SO4)3 + H2 

now we have an unequal number of (SO4) group on both sides of the equation so we put  3H2SO4 instead of H2SO4

2Al + 3H2SO4 → Al2(SO4)3 + H2

now, we have to put 3H2 instead of H2 to make the H atoms equals on both sides.

2Al + 3H2SO4 → Al2(SO4)3 + 3H2 this is the final balanced equation.

∴ the coefficient of  H2SO4 is 3
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A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
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The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

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According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

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