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Dovator [93]
3 years ago
5

If an antelope is running at a speed of 10 mis, and can maintain that horizontal velocity when it jumps, how high must it jump i

n order to clear a horizqntal distance of 20m ? .)
Physics
1 answer:
pochemuha3 years ago
7 0

Answer:

Explanation:

Given

velocity of antelope v=10 m/s

antelope needs to cover a horizontal distance of 20 m

considering horizontal velocity antelope needs to cover 20 m in t sec which is given by

t=\frac{20}{10}=2 s

i.e. in 2 sec antelope needs to jump and return to ground for zero vertical displacement

h=ut+\frac{1}{2}at^2

h=vertical displacement

a=acceleration

t=time

for,  h_{max}, t=1 s

h_{max}=0+\frac{1}{2}g(1)^2

h_{max}=\frac{g}{2}

h_{max}=4.9 m

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A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu
zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

4 0
3 years ago
Choose the situation below in which the force applied is the greatest.
Gnesinka [82]

Answer:

D

Explanation:

We know the formula for Work to be:

W = f * d

Where W is work done

f is force

d is the distance

A)

Work = 50

Distance = 50

So, Force is:

Force = 50/50 = 1

B)

Work = 400

Distance = 80

Force = 400/80 = 5

C)

Work = 365

Distance = 73

Force = 365/73 = 5

D)

Work = 144

Distance = 16

Force = 144/16 = 9

Hence, D is the situation in which the force applied is the greatest.

6 0
3 years ago
5. A box weighs 196 N. A rope is tied to the box. What is the
natta225 [31]

Answer:

296 N

Explanation:

Draw a free body diagram.  The box has two forces on it: tension up and weight down.

Apply Newton's second law:

∑F = ma

T − mg = ma

T = m (g + a)

Given m = 196 N / 9.8 m/s² = 20 kg, and a = +5 m/s²:

T = (20 kg) (9.8 m/s² + 5 m/s²)

T = 296 N

5 0
3 years ago
Someone please help me, I’m so lost my brain hurts
tiny-mole [99]

-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

How much of the heat warms that gram each degree ?

-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

(1/2 calorie) per gram per °C.

That's choice-3 .

7 0
3 years ago
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The index of refraction of a substance is 1.5. Find the sine of the angle of refraction if the sine of the angle of incidence is
Mariulka [41]
We can answer the problem by Snell's Law:

Snell's law<span> (also known as </span>Snell<span>–Descartes </span>law<span> and the </span>law<span> of refraction) is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.</span>
7 0
3 years ago
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