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bija089 [108]
3 years ago
12

Design a fundamental mode asynchronous finite state machine that accepts input pair, A and B. The AB input sequence 00, 01,11, 1

0, 11, 01 is assumed. Z=1 output is produced on the last input (01) of the sequence.a. Develop the primitive flow table with a new stable state under each input for the giver sequence. For a given total stable state, assume other inputs (not in the sequence) are don't cares. b. Determine a reduced flow table to achieve the minimum number of feedback paths. c. Determine a state assignment for the feedback path(s) and show the reduced encoded flow table.

Engineering
1 answer:
dybincka [34]3 years ago
5 0

Answer:

See explaination

Explanation:

A Finite state machines can be synchronous or asynchronous. The operation of asynchronous state machines does not require a clock signal. An Asynchronous state machine is classified basically on their operating mode, such as the fundamental mode, pulse mode or burst mode. An asynchronous state machine can have stable and transient states.

Please kindly refer to attachment for a step by step solution.

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6.28 A six-lane freeway (three lanes in each direction) in rolling terrain has 10-ft lanes and obstructions 4 ft from the right
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Answer:

Assume Base free flow speed (BFFS) = 70 mph

Lane width = 10 ft

Reduction in speed corresponding to lane width, fLW = 6.6 mph

Lateral Clearance = 4 ft

Reduction in speed corresponding to lateral clearance, fLC = 0.8 mph

Interchanges/Ramps = 9/ 6 miles = 1.5 /mile

Reduction in speed corresponding to Interchanges/ramps, fID = 5 mph

No. of lanes = 3

Reduction in speed corresponding to number of lanes, fN = 3 mph

Free Flow Speed (FFS) = BFFS – fLW – fLC – fN – fID = 70 – 6.6 – 0.8 – 3 – 5 = 54.6 mph

Peak Flow, V = 2000 veh/hr

Peak 15-min flow = 600 veh

Peak-hour factor = 2000/ (4*600) = 0.83

Trucks and Buses = 12 %

RVs = 6 %

Rolling Terrain

fHV = 1/ (1 + 0.12 (2.5-1) + 0.06 (2.0-1)) = 1/1.24 = 0.806

fP = 1.0

Peak Flow Rate, Vp = V / (PHV*n*fHV*fP) = 2000/ (0.83*3*0.806*1.0) = 996.54 ~ 997 veh/hr/ln

Vp < (3400 – 30 FFS)

S = FFS

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Density = Vp/S = (997) / (54.6) = 18.26 veh/mi/ln

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