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vovangra [49]
3 years ago
10

An electric dipole consists of charges +2e and -2e separated by 0.82 nm. It is in an electric field of strength 3.2 x 10^6 N/C.

Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field
Physics
1 answer:
Zepler [3.9K]3 years ago
8 0

Explanation:

It is given that,

An electric dipole consists of charges +2e and -2e separated by 0.82 nm

Charge, q=2e=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C

Distance between charges, d=0.82\ nm=0.82\times 10^{-9}\ m

Electric field strength, E=3.2\times 10^6\ N/C

(a) The magnitude of the torque on the dipole is given by :

\tau=p\times E\ sin\theta

When dipole moment is parallel to the electric field, \theta=0

\tau=p\times E\ sin(0)

\tau=0

(b) When the dipole is perpendicular to the electric field, \theta=90

\tau=pE\ sin(90)

\tau=qdE (Since, p = q × d)

\tau=3.2\times 10^{-19}\times 0.82\times 10^{-9}\times 3.2\times 10^6

\tau=8.39\times 10^{-22}\ N.m

(c) When the dipole moment is anti parallel to the electric field, \theta=180

\tau=pE\ sin(180)

Since, sin\ 180=0

\tau=0

Hence, this is the required solution.

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