Answer:
true
Explanation:
H2O : 2 covalent bonds are established between O atom and 2 H atom (H--O--H) by mutual shearing of their valence electrons.
Answer:
- The formation of a peptide bond involves a dehydration reaction.
- A tripeptide contains three amino acid residues.
Explanation:
Peptide bonds are a type of covalent bonds that form between amino acid molecules. A peptide bond links two amino acids together by removing an hydrogen atom from the amine functional group (-NH2) and an hydroxyl (OH) from carboxylic functional group (-COOH) to release a water molecule. Hence, the formation of a peptide bond involves a dehydration reaction i.e loss of water.
This linking of one amino acid to another via a peptide bond forms a polypeptide and consequently a protein molecule. In other words, proteins are polymers of peptides. However, the linkage of three amino acids is called TRIPEPTIDE
The reaction is balanced
The equilibrium constant is defined as the concentration ratio of the products and reactants. They are not considered pure solids and liquids.
So the answer is option B.
Answer:
The statement d) is true: The entropy of the universe is always increased in a spontaneous process.
Explanation:
a), b), c) and e) are false.
a) When no heat exchange occurs between the system and its surroundings
, this process is called an adiabatic process. Because the system does work on the surroundings, w is a negative quantity and there is a decrease in the system’s internal energy (since it cannot exchange heat, it will have to use its internal energy to do work).
b) Breaking a bond will always require energy, whereas forming a bond releases energy. Therefore, if more bonds are broken than formed, the enthalpy of a reaction will be positive.
c) The second law of thermodynamics states that the entropy of the universe increases in a spon
taneous process and remains unchanged in an equilibrium process. Therefore, the entropy of the universe is not always constant.
d) True.
e) According to the Gibbs equation, if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS is smaller in magnitude than ΔH. This condition is met when T is small.
There are 2 full orbitals and 2 electrons left over.
