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____ [38]
2 years ago
8

Methane's chemical formula is CH. Is there a bond between any of the hydrogen atoms? Why or why not? (1 point)

Chemistry
1 answer:
irinina [24]2 years ago
8 0

Answer:

No, there is not because it would form H2 instead of methane if hydrogen bonded with itself.

Explanation:

from the shape of methane which is tetrahedral it's evident there's no hydrogen bond only C-H bond.

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Eukarya cause all cells with nuclei are considered eukaryotic
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The following reaction shows sodium carbonate reacting with calcium hydroxide.
velikii [3]

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


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3 years ago
I will give brainliest (8th grade)
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Answer:

2.The cooling effects of more indirect sunlight cause autumn and winter. Because of the Earth's approximately 23.5º tilt, the seasons in the Northern and Southern Hemispheres are reversed, about six months apart from each other.

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Open the Balancing Chemical Equations interactive and select Introduction mode. Then choose Separate Water. Adjust the coefficie
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<h2>H_2O  + H_2 + O_2</h2>

Explanation:

1. Water decomposition

  • Decomposition reactions are represented by-

       The general equation: AB → A + B.

  • Various methods used in the decomposition of water are -
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  2. Photoelectrochemical water splitting
  3. Thermal decomposition of water
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  • The chemical equation will be -

        H_2O  + H_2 + O_2

Hence, balancing the equation we need to add a coefficient of 2 in front of H_2O on right-hand-side of the equation and  2 in front of H_2 on left-hand-side of the equation.

     ∴The balanced equation is -

       2 H_2O → 2 H_2 + O_2

2. Formation of ammonia

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Hence, for balancing equation we need to add a coefficient of 3 in front of hydrogen and 2 in front of ammonia.

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3 years ago
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