The refractive power of the contact lenses that will enable her to comfortably see objects at distance of 25.0 cm from her eyes is 2.75 D
<h3>Further explanation</h3>
We will solve this problem using following formula:
where:
<em>so = distance of object from lens</em>
<em>si = distance of image from lens</em>
<em>f = focal length of lens</em>
Let's tackle the problem!
<u>Given:</u>
distance of object = s_o = 25.0 cm = 0.25 m
distance of image = s_i = -80.0 cm = -0.80 m<em> ( virtual image )</em>
<u>Unknown:</u>
refractive power = P = ?
<u>Solution:</u>
<h3>Conclusion:</h3>
The refractive power of the contact lenses that will enable her to comfortably see objects at distance of 25.0 cm from her eyes is 2.75 D
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Light
Keywords: Light , Mirror , Magnification , Ray , Diagram , Image , Real , Virtual