Complete question:
Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside this metal resistor? If the potential difference due to electric field between the two ends of the resistor is 10 V.
Answer:
The electric field inside this metal resistor is 3125 V/m
Explanation:
Given;
length of the wire, L = 3.2 mm = 3.2 x 10⁻³ m
diameter of the wire, d = 0.4 mm = 0.4 x 10⁻³ m
the potential difference due to electric field between the two ends of the resistor, V = 10 V
The electric field inside this metal resistor is given by;
ΔV = EL
where;
ΔV is change in electric potential
E = ΔV / L
E = 10 / (3.2 x 10⁻³ )
E = 3125 V/m
Therefore, the electric field inside this metal resistor is 3125 V/m
Answer:
0.021 V
Explanation:
The average induced emf (E) can be calculated usgin the Faraday's Law:
<u>Where:</u>
<em>N = is the number of turns = 1 </em>
<em>ΔΦ = ΔB*A </em>
<em>Δt = is the time = 0.3 s </em>
<em>A = is the loop of wire area = πr² = πd²/4 </em>
<em>ΔB: is the magnetic field = (0 - 1.04) T </em>
Hence the average induced emf is:
Therefore, the average induced emf is 0.021 V.
I hope it helps you!
Answer:
An example in which liquid pressure phenomena can be used in daily life is in Water blasting
Explanation:
Water blasting refers application of pressurized water to remove materials from the surface of objects.
There are different varieties of water blasting, including;
Hydrocleaning; Cleaning enabled by the use of high pressure water
Hydrodemolition; Demolition or removal of concrete using pressurized water
Hydrojetting; The spraying of water under pressure on surfaces in order to remove surface contaminants.
<u>Answer:</u> The number of electrons in given amount of silver are 
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

We are given:
Given mass of silver = 7.1 g
Molar mass of silver = 107.87 g/mol
Putting values in above equation, we get:

Number of electrons in 1 atom of silver = 47
According to mole concept:
1 mole of an element contains
number of particles
So, 0.066 moles of silver will contain = -
number of electrons
Hence, the number of electrons in given amount of silver are 
Answer:
The spring constant = 104.82 N/m
The angular velocity of the bar when θ = 32° is 1.70 rad/s
Explanation:
From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:


Also;

Thus;

where;
= deflection in the spring
k = spring constant
b = remaining length in the rod
m = mass of the slender bar
g = acceleration due to gravity


Thus; the spring constant = 104.82 N/m
b
The angular velocity can be calculated by also using the conservation of energy;






Thus, the angular velocity of the bar when θ = 32° is 1.70 rad/s