Answer:
0.65
Explanation:
For whatever reasons, the parameters are not giving. So, I will assume by myself to make the calculations easier. You can substitute whatever it is to it from your question.
Given that
Radius of the road, r = 63 m
Speed of the car, v = 20 m/s
The relationship between a car that is passing through a curve and it's frictional force is said to be
U(s) * g = v²/r
In the formula above,
U(s) = coefficient of static friction
g = acceleration due to gravity, 9.8 m/s²
v = velocity of the car
r = radius of the road
Now when we substitute the earlier stated values, we have
U(s) * 9.8 = 20² / 63
U(s) * 9.8 = 400 / 63
U(s) * 9.8 = 6.35
U(s) = 6.35 / 9.8
U(s) = 0.65
Thus, our coefficient of static friction, based on the stated values is 0.65
If the pressure is lowered, than the volume must increase. Therefore, when the pressure goes down, the balloons get larger and larger. They may even pop, depending on how full they were to start with. But if they don't pop, when the pressure went back up (you climbed back down to the classroom)... then the balloon would go back to it's normal size.
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
<u>Explanation:</u>
Here, we have Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Let's calculate which student’s measurement has the largest percent error :
<u>A. Student 4: 9.61 m/s2
</u>
Percentage of error = %.
<u>B. Student 3: 9.88 m/s2
</u>
Percentage of error = %.
<u>C. Student 2: 9.79 m/s2
</u>
Percentage of error = % .
<u>D. Student 1: 9.78 m/s2</u>
Percentage of error = % .
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
Answer:
655 nm
Explanation:
When the intereference is destructive then the thickness, d of antireflective film coating one side is given by
2d=w/2n
Where w is wavelength and n is the reflective index of the film
Making w the subject of formula then
w=4nd
Substituting 1.25 for n and 131 nm for d then the wavelength will be
w=4*1.25*131=655 nm
Therefore, the wavelength is equivalent to 655 nm