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4 years ago

A gas made up of atoms escapes through a pinhole times as fast as gas. Write the chemical formula of the gas.

Chemistry

1 answer:

Artemon [7]4 years ago

5 0

A gas made up of atoms escapes through a pinhole 0.225times as fast as gas. Write the chemical formula of the gas.

Answer:

Explanation:

To solve this problem, we must apply Graham's law of diffusion. This law states that "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular mass at constant temperature and pressure".

Mathematically;

$\frac{r_{1} }{r_{2} } = \frac{\sqrt{m_{2} } }{\sqrt{m_{1} } }$

r₁ is the rate of diffusion of gas 1

r₂ is the rate of diffusion of gas 2

m₁ is the molar mass of gas 1

m₂ is the molar mass of gas 2

let gas 2 be the given H₂;

molar mass of H₂ = 2 x 1 = 2gmol⁻¹

rate of diffusion is 0.225;

i .e r1/r2 = 0.225

0.225 = √2 / √ m₁

0.225 = 1.414 / √ m₁

√ m₁ = 6.3

m₁ = 6.3² = 39.5g/mol

The gas is likely Argon since argon has similar molecular mass

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Which separation techniques will you apply for the separation of the following? a) oil from water b) kerosene and petrol c) salt

REY [17]

Answer:

A) Separating funnel method

B) Simple Distillation

C) Evaporation

D) Sublimation

E) It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

Explanation:

B) Kerosene and petrol are both miscible liquids and the difference in their boiling point temperature is not more than 25°C. Thus, we make use of Simple distillation.

C) Can be separated by evaporation where the water is boiled and it evaporates and leaves the salt behind

D) To separate camphor from salt, we use sublimation so the camphor can change directly from solid to the gas state without passing through the liquid state.

E) Chromatography is used to separate components of a mixture.

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7 0

3 years ago

How many moles of CO2 are produced from the combustion of 5.25 moles of CH3OH?

iVinArrow [24]

First, we write the reaction for CH3OH combustion

CH3OH+3/2O2--->CO2+2H2O

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4 0

3 years ago

Calculate the time needed for a constant current of 0.961 a to deposit 0.500 g of co(ii) as

Vera_Pavlovna [14]

1.70 × 10³ seconds

<h3>Explanation </h3>

$\text{Co}^{2+}$ + 2 e⁻ → $\text{Co}$

It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.

Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains $0.500 / 58.933 = 8.484\times 10^{-3} \; \text{mol}$ of Co atoms. It would take $2 \times 8.484 \times 10^{-3} = 0.01697 \; \text{mol}$ of electrons to reduce cobalt (II) ions and produce the $8.484\times 10^{-3} \; \text{mol}$ of cobalt atoms.

Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of $1.637 \times 10^{3} \; \text{C}$ . A current of 0.961 A delivers 0.961 C of charge in one single second. It will take $1.637 \times 10^{3} / 0.961 = 1.70 \times 10^{3} \; \text{s}$ to transfer all these charge and deposit 0.500 g of Co.