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Kitty [74]
3 years ago
15

A gas made up of atoms escapes through a pinhole times as fast as gas. Write the chemical formula of the gas.

Chemistry
1 answer:
Artemon [7]3 years ago
5 0

A gas made up of atoms escapes through a pinhole 0.225times as fast as gas. Write the chemical formula of the gas.

Answer:

Explanation:

To solve this problem, we must apply Graham's law of diffusion. This law states that "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular mass at constant temperature and pressure".

Mathematically;

                 \frac{r_{1} }{r_{2} }  = \frac{\sqrt{m_{2} } }{\sqrt{m_{1} } }

r₁ is the rate of diffusion of gas 1

r₂ is the rate of diffusion of gas 2

m₁ is the molar mass of gas 1

m₂ is the molar mass of gas 2

let gas 2 be the given H₂;

   molar mass of H₂ = 2 x 1 = 2gmol⁻¹

rate of diffusion is 0.225;

  i .e r1/r2 = 0.225

          0.225 = √2  /  √ m₁

           0.225 = 1.414 / √ m₁

           

       √ m₁  = 6.3

           m₁  = 6.3²  = 39.5g/mol

The gas is likely Argon since argon has similar molecular mass

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A student makes a mistake while preparing a vitamin C sample for titration and adds the potassium iodide solution twice. How wil
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The added KI does not have any impact  

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the excess iodine is free reacts with the starch  indicator, forming the blue-black starch-iodine complex.  

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Answer B

Hope this helps!

5 0
3 years ago
RATE LAW QUESTION !
vivado [14]
In general, we have this rate law express.:

\mathrm{Rate} = k \cdot [A]^x [B]^y
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4)  by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation \Delta \mathrm{Rate} = \Delta [B]^y

3.09 = (3)^y \implies y \approx 1

To this point, \mathrm{Rate} = k \cdot [A]^x [B]^1

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for \Delta \mathrm{Rate} = \Delta [A]^x

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Difference between clinical and laboratory thermometer
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Answer:

1)clinical thermometer has temperature range 35 to 42degree celcius where labouratery thermometer has -10 to 110 degree celcius.

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7 0
3 years ago
Read 2 more answers
The volume of a single tungsten atom is 1.07×10-23 cm3. What is the volume of a tungsten atom in microliters?
vesna_86 [32]

Answer: 1.07×10^-20microlitre

Explanation:

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