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aev [14]
3 years ago
8

Atoms that emit particles and energy from their nuclei are

Physics
1 answer:
saw5 [17]3 years ago
4 0
Atoms that emit particles and energy from their nuclei are (Radioactive).
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Technological advances are now making it possible to link visible-light telescopes so that they can achieve the same angular res
leonid [27]

Answer: The angle of resolution =47.05°

Explanation:

The angle of resolution represents the resolve power and precision of optical instruments such as the eye, camera and e en a microscope. It is given by the equation:

Sin A = 1.220(W÷D)

Sin A= 1.220(300÷500)

Sin A = 1.220(0.6)

Sin A = 0.732

A= Sin^-1 0.732

A= 47.05°

4 0
3 years ago
Read 2 more answers
How is work involved in stopping a car?
vichka [17]
You have to move your foot to stop the car so I guess that would be considered work by moving your foot
5 0
3 years ago
Read 2 more answers
A 3.9 kg ball traveling towards a soccer player at a velocity of -3.5 m/s rebounds off the soccer player's foot at a velocity of
Tresset [83]

Answer: 2.92 s

Explanation:

Given

Mass of ball is m=3.9\ kg

The initial velocity of the ball is u=-3.5\ m/s

Velocity after the rebound is v=15.9\ m/s

Force during the contact is F=25.9\ N

We know, change in momentum is Impulse

\Rightarrow F\cdot \Delta t=m(\Delta v)

\Rightarrow 25.9\cdot \Delta t=3.9(15.9-(-3.5))\\\\\Rightarrow \Delta t=\dfrac{3.9\times 19.4}{25.9}=2.92\ s

Thus, the force is applied for 2.92 s

4 0
3 years ago
Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an
Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0
4 years ago
A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

5 0
4 years ago
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