<span>26.833 liters
Aluminum oxide has a formula of Al</span>₂O₃,<span> which means for every mole of aluminum used, 1.5 moles of oxygen is required (3/2 = 1.5).
Given 42.5 g of aluminum divided by its atomic mass (26.9815385) gives 1.575 moles of aluminum.
Since it takes 1.5 moles of oxygen per mole of aluminum to make aluminum oxide, you'll need 2.363 moles of oxygen atoms.
Each molecule of oxygen gas has 2 oxygen atoms, so the moles of oxygen gas will be 2.363/2 = 1.1815
Finally, you need to calculate the volume of </span>1.1815 <span>moles of oxygen gas.
1 mole of gas at STP occupies 22.7 liters of volume. Therefore,
1.1815 * 22.7 = </span>26.8 liters <span>of oxygen gas.
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Answer:
Correc option: 
Explanation:
size of atom : it says somthing about how many shell present in a particular atom or ion and it can also be evaluated on the basis of radius of atom.
Br^- and Kr has highest number of shell as compared to other group of species .
Na ,S , Mg ,P all are from 3rd period but Kr and Br^- in the 4th period so size of species of this group will more,
Size increases on increasring the shell number
The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
<h3>How to calculate [H3O+]?</h3>
The hydrogen ion concentration of a solution can be calculated as follows:
pOH = - log [OH-]
pOH = - log [6.3 × 10-⁷M]
pOH = - [-6.2]
pOH = 6.2
Since pOH + pH = 14
pH = 14 - 6.2
pH = 7.8
pH = - log [H3O+]
7.8 = - log [H3O+]
[H3O+] = 10-⁷:⁸
[H3O+] = 1.5 × 10-⁸M
Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
Learn more about hydrogen ion concentration at: brainly.com/question/15082545
Answer:
45.02 L.
Explanation:
- Firstly, we need to calculate the no. of moles of water vapor.
- n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.
- We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.
<em><u>Using cross multiplication:</u></em>
1.0 mole of CO occupies → 22.4 L.
2.01 mole of CO occupies → ??? L.
∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.
