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kow [346]
3 years ago
12

The characteristic functional groups of a protein are _____.

Chemistry
1 answer:
V125BC [204]3 years ago
4 0

Answer:

\boxed{\text{amide groups}}

Explanation:

A protein is a long chain of amino acids linked together by amide groups.

The general structure is

\rm \left[-NHCHR-\underbrace{\hbox{CO-NH}}_{\hbox{amide group}}-CHRCO-\right]_{n}

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The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (
harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as  Rate=k[H_2O_2]

Part b: The integrated Rate Law is given as [H_2O_2]=[H_2O_2]_0 e^{-kt}

Part c: The value of rate constant is 7.8592 \times 10^{-4} s^{-1}

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of H_2O_2, the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

Rate=k[H_2O_2]

Part b

Integrated Rate Law

The integrated Rate Law is given as

[H_2O_2]=[H_2O_2]_0 e^{-kt}

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}

The value of rate constant is 7.8592 \times 10^{-4} s^{-1}

Part d

Concentration after 4000 s is given as

-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M

Concentration after 4000 s is 0.043 M.

7 0
3 years ago
What is the wavelength of a wave with a<br>velocity of 50 m/s and a frequency of 5 Hz?​
pentagon [3]

Answer:

Wavelength is 10m

Explanation:

To solve this problem, we use the formula for wavelength

Wavelength = wave velocity / frequency

Wavelength = 50m/s / 5Hz

= 10m

8 0
3 years ago
What mass of Al would be obtained from the complete reduction of 10.2 tonnes of Al2O3?
Fynjy0 [20]

Answer:

5.4 tonnes.

Explanation:

The first step is to find the molar mass of Al2O3. Aluminum has a molar mass of about 27 and oxygen has a molar mass of about 16, so 2(27)+3(16)= 102g/mol=0.102kg/mol. 10200kg/0.102kg/mol=100,000 moles of Al2O3 in 10.2 tonnes. Multiplying this by the molar mass of the two aluminums, you get a total of 54*100,000=5400000g=5400kg=5.4 tonnes. Hope this helps!

3 0
3 years ago
The molar enthalpy of
nika2105 [10]

Answer:

vaporization

Explanation:

The molar enthapy of _vaporization______ is the heat required to vaporize one mole of a liquid”

7 0
4 years ago
Find the relationships between the variables affected by gas:
butalik [34]

PV=nRT

Where:

P= pressure

V= volume

n= mol

R= universal gas constant

T= temperature

To get number of particles : apply the following equation.

n = N/L

Where ;

n =mol

N =number of particles

L =avagadro constant

3 0
4 years ago
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