Ask question

Ask question

All categories

Montano1993 [528]

3 years ago

7

What beat frequencies result if a piano hammer hits three strings that emit frequencies of 392.0, 587.3, and 146.8 hz? (enter yo

ur answers from smallest to largest.)?

1 answer:

FinnZ [79.3K]3 years ago

3 0

128.1-127.8= 0.3Hz
<span>129.1-128.1= 1.0Hz </span>
<span>129.1-127.8= 1.3Hz</span>

You might be interested in

Can u help me with C

Vladimir79 [104]

I believe it would be 2m/s.

6 0

3 years ago

Read 2 more answers

Which of the following is true? A. If an equal force is applied to two objects, the object with greater mass will accelerate mor

docker41 [41]

B

I hope this helps and have a wonderful day filled with joy!!

<3

4 0

3 years ago

Why is natural gas referred to as a fossil fuel?

Yuri [45]

I believe it would be choice A. but not 100% possitive

7 0

2 years ago

_________ forces exist between objects that are not in contact with each other.

AveGali [126]

Contact forces is the answer

7 0

2 years ago

If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge thr

Agata [3.3K]

Answer:

Resistance in the flash tube, $R=3.97\times 10^{-3}\ \Omega$

Explanation:

It is given that,

Speed of the bullet, v = 500 m/s

Distance between one RC constant, d = 1 mm = 0.001 m

Capacitance, $C=503\ \mu F=503\times 10^{-6}\ F$

The time constant of RC circuit is given by :

$\tau=RC$

R is the resistance in the flash tube

$R=\dfrac{\tau}{C}$ ..........(1)

Speed of the bullet is given by total distance divided by total time taken as :

$v=\dfrac{d}{\tau}$

$\tau=\dfrac{d}{v}$

$\tau=\dfrac{0.001}{500}$

$\tau=0.000002\ s$

Equation (1) becomes :

$R=\dfrac{0.000002}{503\times 10^{-6}}$

$R=3.97\times 10^{-3}\ \Omega$

So, the resistance in the flash tube is $3.97\times 10^{-3}\ \Omega$ . Hence, this is the required solution.

8 0

2 years ago

Read 2 more answers