Answer:
Explanation:
Given
Total time=27 min 43.6 s=1663.6 s
total distance=10 km
Initial distance 
time taken=25 min =1500 s
initial speed 
after 8.13 km mark steve started to accelerate
speed after 60 s


distance traveled in 60 sec


time taken in last part of journey

distance traveled in this time


and total distance



(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
<h3>
Work done by the applied force</h3>
The work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
<h3>Work done by frictional force</h3>
W = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
<h3>Net work done by all the forces on the tractor</h3>
W(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
Learn more about work done here: brainly.com/question/25573309
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22.5 J
Explanation:
Given:
x = 3 m

The spring potential energy
is


Answer:

Explanation:
Kinematics equation for constant acceleration:

Answer:
434.16 Joules
Explanation:
u = Initial velocity
v = Final velocity
m = Mass of person
From work-energy theorem

The runner loses 434.16 Joules of mechanical energy.

He slides 0.94364 m