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3 years ago

How many atoms in the formula Be (NO3)2

1 answer:

3 0

The compound calcium nitrate consists of a total of nine atoms, including one atom of calcium, two of nitrogen and six of oxygen.

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How do I solve this?

Xelga [282]

Answer:

Explanation:

When you divide exponentials, you subtract the powers. For the numbers infront, just use a basic calculator for.

7.95/6.02 = 1.32

10^22/10^23 = 10^-1

1.32 x 10^-1 is your answer

7 0

3 years ago

DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction. 2 C6H5Cl + C2HOCl3 → C14H9Cl5 + H

Elena-2011 [213]

Answer:

1,070.41 grams of DDT will be formed .Explanation:

1) $2 C_6H_5Cl + C_2HOCl_3\rightarrow C_{14}H_9Cl_5 + H_2O$

Moles of chlorobenzene = $\frac{1197 g}{112.5 g/mol}=10.64 mol$

According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :

$\frac{1}{2}\times 10.64 mol=5.32 mole$ of chloral

2) Moles of chloral = $\frac{456 g}{147.5 g/mol}=3.0915 mol$

According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :

$\frac{2}{1}\times 3.0915 mol=6.1830 mol$ of chloro benzene

As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.

According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :

$\frac{1}{1}\times 3.0195 mol=3.0195 mol$

Mass of 3.0195 moles of DTT :

3.0195 mol × 354.5 g/mol = 1,070.41 g

1,070.41 grams of DDT will be formed .

3 0

3 years ago

What is the percent composition by mass of hydrogen in nh4hco3

Simora [160]

Answer: The percent composition by mass of hydrogen in given compound is 6.33 %

Explanation:

We are given:

A chemical compound having chemical formula of $NH_4HCO_3$

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

$\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100$

Mass of compound = $[(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol$

Mass of hydrogen = $(5\times 1)=5g/mol$

Putting values in above equation, we get:

$\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%$

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0

3 years ago

g 2BrO3- + 5SnO22-+ H2O5SnO32- + Br2+ 2OH- In the above reaction, the oxidation state of tin changes from to . How many electron

Archy [21]

Answer:

In the above reaction, the oxidation state of tin changes from 2+ to 4+.

10 moles of electrons are transferred in the reaction

Explanation:

Redox reaction is:

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

SnO₂²⁻ → SnO₃²⁻

Tin changes the oxidation state from +2 to +4. It has increased it so this is the oxidation from the redox (it released 2 e⁻). We are in basic medium, so we add water in the side of the reaction where we have the highest amount of oxygen. We have 2 O on left side and 3 O on right side so we add 1 water on the right and we complete with OH⁻ in the opposite side to balance the H.

SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O Oxidation

BrO₃⁻ → Br₂

First of all, we have unbalance the bromine, so we add 2 on the BrO₃⁻. We have 6 O in left side and there are no O on the right, so we add 6 H₂O on the left. To balance the H, we must complete with 12OH⁻. Bromate reduces to bromine at ground state, so it gained 5e⁻. We have 2 atoms of Br, so finally it gaines 10 e⁻.

6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ Reduction

In order to balance the main reaction and balance the electrons we multiply (x5) the oxidation and (x1) the reduciton

(SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O) . 5

(6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻) . 1

5SnO₂²⁻ + 10OH⁻ + 6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ + 5SnO₃²⁻ + 10e⁻ + 5H₂O

We can cancel the e⁻ and we substract:

12OH⁻ - 10OH⁻ = 2OH⁻ (on the right side)

6H₂O - 5H₂O = H₂O (on the left side)

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

6 0

3 years ago

What is the value for ∆Soreaction for the following reaction, given the standard entropy values?

Soloha48 [4]

To get the ∆S of the reaction, we simply have to add the ∆S of the reactants and the ∆S of the products. Then, we get the difference between the ∆S of the products and the ∆S of the products. If the ∆S is negative, then the reaction spontaneous. If the otherwise, the reaction is not spontaneous.

8 0

3 years ago