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saveliy_v [14]
3 years ago
6

In the fluid-flow analogy for electrical circuits, what is analogous to a conductor?

Engineering
1 answer:
Vedmedyk [2.9K]3 years ago
8 0
I am going to say a pump
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It is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water entering at 20 °C?
vovangra [49]

Answer:

Yes, it is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water that is entering at 20 °C because this temperature (20 °C) of the external cooling water is less than the saturation temperature of steam which is which is 45.81 °C, and heated by a boiler; as a result of this condition, coupled with the assumption that the turbine, pump, and interconnecting tube are adiabatic, and the condenser exchanges its heat with the external cooling river water, it possible to maintain a pressure of 10 kPa.

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4 years ago
Bending is defined as? A. the application of a load tending to distort a member in one direction. B. the application of opposing
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What is the volicity of a rocket?
Marysya12 [62]

Answer:

7.9 kilometers per second

Explanation:

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3 years ago
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What is electricity defined as
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Exact answer: a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.

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3 years ago
A steam turbine has isentropic efficiency of 0.8. Isentropically, it is supposed to deliver work of 100 kW. What is the actual w
trapecia [35]

Answer:

80 kW; 11 kW; 8 kW; 0.6

Explanation:

Part 1

Isentropic turbine efficiency:  

\eta_t = \frac{\text{Real turbine work}}{\text{isentropic turbine work}} = \frac{W_{real}}{W_s}

W_{real} = \eta_t*W_s

W_{real} = 0.8*100 kW

W_{real} = 80 kW

Part 2

Coefficient of performance COP is defined by:

COP = \frac{Q_{out}}{W}

Q_{out} = W*COP

Q_{out} = 5 kW*2.2

Q_{out} = 11 kW

Part 3

(a)

Energy balance for a refrigeration cycle gives:

Q_{in} + W = Q_{out}

3 kW + 5 kW = Q_{out}

8 kW = Q_{out}

(b)

COP = \frac{Q_{in}}{W}

COP = \frac{3 kW}{5 kW}

COP = 0.6

3 0
3 years ago
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