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3 years ago

6

In the fluid-flow analogy for electrical circuits, what is analogous to a conductor?

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

I am going to say a pump

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Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. Technician B says that latent heat is

AysviL [449]

Answer: C

Both A and B are correct

Explanation:

Latent heat is the hidden heat.

Latent heat is the heat energy required to change one state of matter to another state of matter without change in temperature. For example, solid state to liquid state, or liquid state to gaseous state.

Thermometer can not detect the latent heat. That is why it is called hidden heat.

If Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. And Technician B says that latent heat is hidden heat that is required for a change of state of matter, then we can therefore conclude that both Technician A and Technician B are correct.

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3 years ago

A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?

Ierofanga [76]

Answer: (b)

Explanation:

Given

Original length of the rod is $L=100\ cm$

Strain experienced is $\epsilon=82\%=0.82$

Strain is the ratio of the change in length to the original length

$\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm$

Therefore, new length is given by (Considering the load is tensile in nature)

$\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm$

Thus, option (b) is correct.

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3 years ago

Hello, how are you?

Kisachek [45]

Answer:

Hello, I'm good. Thank you for asking

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2 years ago

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Calculate the amount of power (in Watts) required to move an object weighing 762 N from point A to point B within 29 seconds. Di

Tresset [83]

Answer:

0.556 Watts

Explanation:

w = Weight of object = 762 N

s = Distance = 5 m

t = Time taken = 29 seconds

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow a=\frac{2\times (s-ut)}{t^2}\\\Rightarrow a=\frac{2\times (5-0)}{29^2}=\frac{10}{481}$

Mass of the body

$m=\frac{w}{g}=\frac{762}{9.81}$

Force required to move the body

$F=ma\\\Righarrow F=\frac{762}{9.81}\times \frac{10}{481}$

Velocity of object

$v=u+at\\\Rightarrow v=0+\frac{10}{481}\times 29\\\Rightarrow v=\frac{10}{29}$

Power

$P=Fv\\\Rightarrow P=\frac{762}{9.81}\times \frac{10}{481}\times \frac{10}{29}=0.556\ W$

∴ Amount of power required to move the object is 0.556 Watts

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3 years ago

A 1/20 scale model of a wing is used to determine forces on the actual airplane. the 1/20 scale refers to the:_____

Kryger [21]

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

5 0

3 years ago

Read 2 more answers