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sergeinik [125]
3 years ago
6

Hi :) what’s the difference between conduction in metals & non-metals ? I know it’s the free electron diffusion thingy but I

really don’t understand it at all. anyone able to help? Thank you!
Physics
1 answer:
Andre45 [30]3 years ago
8 0

The difference between metal and non-metal in terms of condition is explained below.

Explanation:

  • In metals, conduction occurs due to the aggregation of vibrations of molecules and free-electron distribution. While in non-metals, the mechanism for conduction is only atomic or molecular vibrations.
  • Apart from free electrons, there are phonons in metals as well as non-metals. Non-metals hold a confined amount of thermal conductivity only due to Phonons and Lattice vibrations.
  • Concerning atomic vibration in a solid thing (non-metals mainly), it is easier to know if one receives the fact that atoms are almost floating adjacent to one another depending on the covalent bonds between them.
  • When a metal is heated the electrons quickly respond to the heat and transfer it to the nearby atom or solid touching it. As non-metals don't possess free electrons, the heat transfer happens due to phonons (the excited state of the lattice structure vibrating uniformly).
  • In metals, this rarely plays a role as the electrons transfer most of the heat efficiently.
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3 years ago
If a power utility were able to replace an existing 500 kV transmission line with one operating at 1 MV, it would change the amo
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Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

initial voltage in the transmission line, V₁ = 500 kV = 500,000 V

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P = \frac{V^2}{R}

Power lost in the first wire;

P_1 = \frac{V_1^2}{R}

R = \frac{V_1^2}{P_1}

Power lost in the second wire

P_2 = \frac{V_2^2}{R}\\\\ R = \frac{V_2^2}{P_2}

Keeping the resistance constant, we will have the following equation;

\frac{V_2^2}{P_2} = \frac{V_1^2}{P_1} \\\\P_2 = \frac{V_2^2P_1}{V_1^2}\\\\

P_2 = \frac{(1,000,000)^2P_1}{(500,000)^2}\\\\P_2 =4P_1

Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.

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3 years ago
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Answer:

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F = μmg = 0.2(2.02)(9.8) = 3.96 N

3.96d = 15.84

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