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sergeinik [125]
3 years ago
6

Hi :) what’s the difference between conduction in metals & non-metals ? I know it’s the free electron diffusion thingy but I

really don’t understand it at all. anyone able to help? Thank you!
Physics
1 answer:
Andre45 [30]3 years ago
8 0

The difference between metal and non-metal in terms of condition is explained below.

Explanation:

  • In metals, conduction occurs due to the aggregation of vibrations of molecules and free-electron distribution. While in non-metals, the mechanism for conduction is only atomic or molecular vibrations.
  • Apart from free electrons, there are phonons in metals as well as non-metals. Non-metals hold a confined amount of thermal conductivity only due to Phonons and Lattice vibrations.
  • Concerning atomic vibration in a solid thing (non-metals mainly), it is easier to know if one receives the fact that atoms are almost floating adjacent to one another depending on the covalent bonds between them.
  • When a metal is heated the electrons quickly respond to the heat and transfer it to the nearby atom or solid touching it. As non-metals don't possess free electrons, the heat transfer happens due to phonons (the excited state of the lattice structure vibrating uniformly).
  • In metals, this rarely plays a role as the electrons transfer most of the heat efficiently.
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Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?
Mice21 [21]

Answer:

30 Watts

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 Power = Work/Time

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5 0
3 years ago
Consider an object with weight on the Earth W_earth. The gravity of the Earth is g. If it is moved to another planet with gravit
Mazyrski [523]

Answer:

W_{Planet} = \frac{W_{Earth}}{g}\times a

Explanation:

We know that weight of an object on Earth is,

W_{Earth} = m\times g

Thus,

m = \frac{W_{Earth}}{g}

where,

m = mass of an object, which is constant and is independent of gravity

g = acceleration due to gravity on Earth

On the new planet, gravity = a

Thus the weight of the object on the new planet will be

W_{Planet} = m\times a

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5 0
3 years ago
A certain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) Fi
Ratling [72]

Answer:

(a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

Put  the value into the formula

-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2

u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}

u=-2.496\ m/s

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

v = u+gt

Put the value in the equation

-2.496=0-9.8\times t

t =\dfrac{2.496}{9.8}

t=0.254\ sec

The total time is

t'=t+1.95

t'=0.254+1.95

t'=2.204\ sec

We need to calculate the distance

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times9.8\times(2.204)^2

s=23.80\ m

Hence, (a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

4 0
3 years ago
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