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4 years ago

6

Two types of specialized fingerprint

1 answer:

Akimi4 [234]4 years ago

7 0

Two types of fingerprints are

.1. arches

2. loopes

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The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el

Nana76 [90]

Answer:

E

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

7 0

4 years ago

During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 31.7 rad/s. Find the angular displ

Crank

Answer:

$\Delta \theta = 3116.11\,rad$ and $\Delta \theta = 495.944\,rev$

Explanation:

The tub rotates at constant speed and the kinematic formula to describe the change in angular displacement ( $\Delta \theta$ ), measured in radians, is:

$\Delta \theta = \omega \cdot \Delta t$

Where:

$\omega$ - Steady angular speed, measured in radians per second.

$\Delta t$ - Time, measured in seconds.

If $\omega = 31.7\,\frac{rad}{s}$ and $\Delta t = 98.3\,s$ , then:

$\Delta \theta = \left(31.7\,\frac{rad}{s} \right)\cdot (98.3\,s)$

$\Delta \theta = 3116.11\,rad$

The change in angular displacement, measured in revolutions, is given by the following expression:

$\Delta \theta = (3116.11\,rad)\cdot \left(\frac{1}{2\pi} \frac{rev}{rad} \right)$

$\Delta \theta = 495.944\,rev$

6 0

3 years ago

Does heating a metal wire increase or decrease its electrical resistance? Why?

Veseljchak [2.6K]

Heating any electrical conductor makes it's resistance INcrease.

4 0

4 years ago

What is the efficiency of an engine that exhausts 440 J of heat to a cold reservoir and receives 570 J of heat from a hot reserv

katrin2010 [14]

Answer:

Efficiency = 77%

Explanation:

Input energy = 570 J

Output energy = 440 J

To find the efficiency;

$Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100$

Substituting into the equation, we have;

$Efficiency = \frac {440}{570} * 100$

$Efficiency = 0.7719 * 100$

Efficiency = 77.19 ≈ 77%

Therefore, the efficiency of the engine is 77 percent.

7 0

3 years ago

A 0.09 g honeybee acquires a charge of +23 pc while flying. The earth's electric field near the surface is typically (100 N/C, d

hodyreva [135]

Answer:

$2.6\times 10^{-5}$

Explanation:

<u>Given:</u>

$m$ = mass of the honeybee = 0.09 g = $9\times 10^{-5}\ kg$

$q$ = charge on the honeybee = 23 pC = $2.3\times 10^{-11}\ C$

$E$ = electric field near the surface of earth = 100 N/C

<u>Assume:</u>

$g$ = acceleration due to gravity = $9.8\ m/s^2$

$W$ = weight of the honeybee

$F$ = electric force on the honeybee

$R$ = ratio of the electric force and the weight of the honeybee

We know that

$F = qE\,\,\, and\,\,\, W = mg\\\therefore R = \dfrac{F}{W}\\\Rightarrow R = \dfrac{qE}{mg}\\\Rightarrow R = \dfrac{2.3\times 10^{-11}\ C\times 100 N/C}{9\times 10^{-5}\ kg\times 9.8\ m/s^2}\\\Rightarrow R = 2.6\times 10^{-6}$

So, the ration of the electric force on the bee to its weight is $2.6\times 10^{-6}$ .

On multiplying this ration by 10, the ratio becomes $2.6\times 10^{-5}$ .

8 0

4 years ago