Answer:
55.5g of N₂
Explanation:
It is possible to find ΔH of a reaction by the sum of half-reaction (Hess's law), thus:
<em>(1) </em>4 NH₃ + 3 O₂ → 2 N₂ + 6 H₂O ΔH= -1556KJ
<em>(2) </em>N₂O + H₂ → N₂ + H₂O ΔH= -389.4 KJ
<em>(3) </em>H₂+ ½ O₂ → H₂O ΔH= -223.9 KJ
(4) = 1/2 (1) + 3 (2):
<em>(4) </em>2 NH₃ + 3 N₂O +3 H₂ + ³/₂ O₂ → 4 N₂ + 6 H₂O
ΔH = 1/2 (-1556kJ) + 3 (-389.4kJ) = -1946.2kJ
(4) - 3(3):
2 NH₃ + 3 N₂O → 4 N₂ + 3 H₂O ΔH = -1946.2kJ - 3 (-223.9 KJ)
ΔH = -1274.5 kJ
As when 5 moles of nitrogen are produced there are released 1274.5kJ, when are released 505kJ:
505kJ × (5 moles N₂ / 1274.5kJ) =<em> 1.98 moles of N₂. </em>In mass:
1.98moles N₂ ₓ (28g / 1mol) = <em>55.5g of N₂</em>
Galactic recycling is a natural phenomenon in which the stars expel some gas into the space so that it would mix with the interstellar medium. As a result, this would produce new younger stars. So, basically, the concept done here is the mass and energy conservation. In order to create new species, the energy must come from another source.
<u>Answer:</u> The equilibrium constant for the given reaction is 0.8
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as
For the general equation:
The equilibrium constant is represented as:
For the given chemical equation:
for this equation is given by:
Concentration at equilibrium of
Putting values in above equation, we get:
Hence, the equilibrium constant for the given chemical reaction is 0.8
Answer:
Answer in explanation
Explanation:
a. Boron , element 5
Helium has 2 electrons, add to the other 3 to give 5.
Other group members are : Aluminum Al, Gallium Ga, Indium In , Thallium Tl and Nihonium Nh
b. Sulphur, element 16
Neon is 10 , add other 6 electrons to make 16
Other group members are: Oxygen O, selenium Se , Tellurium Te and Polonium Po
c. Lanthanum, element 57
Xenon is 54, add the other 3 electrons to give 57.
Other elements in group : Scandium Sc , Yttrium Y , Actinium Ac, Lutetium Lu and/or Lawrencium Lr