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Rama09 [41]
3 years ago
13

Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 590 m3/s at a location 90 m above the lake s

urface. Determine the total mechanical energy of the river water per unit mass and the power generation potential of the entire river at that location. We take the density of water to be rho = 1000 kg/m3. The total mechanical energy of the river water per unit mass is kJ/kg. The power generation potential of the entire river at that location is kW.
Physics
1 answer:
Norma-Jean [14]3 years ago
8 0

Explanation:

Given data

Velocity v=3 m/s

Water volume flow rate V=590 m³/s

Water elevation z=90 m

Water density p=1000 kg/m³

First we need to determine the energy per unit mass

So

e_{mech:}=e_{kine:}+e_{potent:}\\e_{mech:}=e_{potent:}\\e_{mech:}=gz\\e_{mech:}=9.81m/s*90m\\e_{mech:}=882.9J/kg\\or\\e_{mech:}=0.8829kJ/kg

Now the power generation potential is:

\\W=m.e_{mech:}\\where\\m=pV_{volume}\\So\\W=pV_{volume}e_{mech:}\\W=1000kg/m^{3}*590m^{3}/s*882.9j/kg\\W=5.21*10^{8}W\\or\\W=520911kW\\or\\W=521MW

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Ivenika [448]

As the jumper goes farther and farther down in each picture they are going farther and farther away from the bridge. Except for when they go back up then they are getting closer to the bridge. The bridge has no momentum while the jumper does which is why the bridge stays the same and the jumper is moving farther away due to his downward momentum.

5 0
3 years ago
A steel ball is dropped from a building's roof and passes a window, taking 0.12 s to fall from the top to the bottom of the wind
Dvinal [7]
The top of the WINDOW is 19 meters from the ground. also steel balls dont bounce.
8 0
4 years ago
A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?
frosja888 [35]

Given:

The mass of the ball is

m=1.23\text{ kg}

The speed of the ball is

\begin{gathered} v=65.8\text{ mi/h} \\  \end{gathered}

Required: calculate the kinetic energy of the baseball

Explanation: to calculate the kinetic energy of a body we will use the formula as

K.E=\frac{1}{2}mv^2

first, we convert velocity from mi/h into m/s.

we know that

1\text{ mi=1609.34 m}

and

1\text{ h=3600 sec}

then the velocity is

\begin{gathered} v=\frac{65.8\times1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}

now plugging all the values in the above formula, we get

\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}

Thus, the kinetic energy of the baseball is

527.61\text{ J}

4 0
2 years ago
An empty train car of mass 2.0 x 10^4 kg coasts along at 10 m/s. A 3000-kg boulder is suddenly dropped vertically into the car.
Zepler [3.9K]

Answer:8.69 m/s

Explanation:

Given

mass of Empty train m=2\times 10^4 kg

velocity of car v=10 m/s

mass of Boulder M=3000 kg

Since no External force is acting therefore conserving Momentum

Train and boulder moves with same velocity after collision

m v=(M+m)v'

2\times 10^4\times 10=(2\times 10^4+3000)v'

v'=\frac{20,000\times 10}{23000}

v'=8.69 m/s

8 0
3 years ago
you are sitting at the center of a large turntable at an amusement park as it is set spinning freely. you decide to crawl toward
larisa [96]

You are sitting at the center of a large turntable at an amusement park as it is set spinning freely. You decide to crawl towards the edge of the turntable. Rotational speed will decrease

There is no external torque

hence , the angular momentum of the table is conserved

L (initial) = L ( final)

since , L = m*v*r

where

m = mass

v = velocity

r = radius

If  the person is crawled towards the outer rim, then the rotational inertia of the turntable will increase. In order to conserve the angular momentum , its rotational speed will decrease as mass and radius cannot be altered .

To learn more about torque here :

brainly.com/question/19104073

#SPJ4

7 0
1 year ago
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