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Dvinal [7]
3 years ago
6

Which characteristic does an object with a constant acceleration always have?

Physics
2 answers:
9966 [12]3 years ago
8 0

Explanation:

By definition, the word acceleration is equal to the rate of change of velocity. Mathematically, it is given by :

a=\dfrac{dv}{dt}

dv=a.dt

v=\int\limits^t_0 {a.dt}

Since, it is given that acceleration is constant

v=at+v_o

v₀ is the constant of integration and it corresponds to initial velocity

From above equation, it is clear that when acceleration is constant the speed varies linearly. Hence, when an object move with constant acceleration, it always changes its velocity.

lapo4ka [179]3 years ago
5 0
It always has changing velocity
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A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.
raketka [301]

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

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2 years ago
How much work is done to move 2.10 μC of charge from the negative terminal to the positive terminal of a 3.50 V battery?
rjkz [21]

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6.3E-6

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4 0
3 years ago
Machmer Hall is 400 m North and 180 m West of Witless.
yan [13]

Answer:

The distance from Witless to Machmer is 438.63 m.

Explanation:

Given that,

Machmer Hall is 400 m North and 180 m West of Witless.

We need to calculate the distance

Using Pythagorean theorem

D = \sqrt{(d_{m})^2+(d_{w})^2}

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d_{w} =distance of Witless

Put the value into the formula

D = \sqrt{(400)^2+(180)^2}

D=438.63\ m

Hence, The distance from Witless to Machmer is 438.63 m.

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