A circular loop with radius R= 20 cm carrying a current, I= 5 A is placed in a uniform magnetic field B = 0.2 T. (a) Find the ma
1 answer:
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Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
= (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = -
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = -
v₁ = -0.8087 m / s
Answer:
(a)
(b) neither increasing or decreasing
(c) opposite to the flow of charge carriers
Explanation:
The current through an inductor of inductance L is given by:
(1)
(a) The induced emf is given by the following formula
(2)
You derivative the expression (1) in the expression (2):
(b) At t=0 the current is zero
(c) At t = 0 the emf is:
w, L and Imax have positive values, then the emf is negative. Hence, the induced emf is opposite to the flow of the charge carriers.
(d) read the text carefully