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gayaneshka [121]
2 years ago
9

A circular loop with radius R= 20 cm carrying a current, I= 5 A is placed in a uniform magnetic field B = 0.2 T. (a) Find the ma

gnitude of the magnetic dipole moment of the current loop. (b) Find the maximum torque acting on the loop. (c) How much work is needed to rotate this loop in this field by 90°, starting from the initial position, 0, =0° to a final position, 0r=90° ? Hint: 0 is the angle between the magnetic dipole moment and the magnetic field​
Physics
1 answer:
Veronika [31]2 years ago
8 0
Yes it is thag answer I swear
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Answer: 500 s

Explanation:

Speed v is defined as a relation between the distance d and time t:

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Where:

v=3(10)^{8}m/s is the speed of light in vacuum

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Isolating t:

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Finally:

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Converting back to direction and magnitude, we get \langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle

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