Which element has the electron configuration [Rn] 7s2 5f14 6d4 ?

Chemistry

2 answers:

nexus9112 [7]4 years ago

3 0

Answer:

Rn] 5f14 6d4 7s2 mp: none d: none. Seaborgium ..... Element. Density. Boiling or Melting Point in °C. Electron Configuration. Symbol.

Explanation:

solmaris [256]4 years ago

3 0

Answer: The element having given configuration is Seaborgium.

Explanation:

Electronic configuration tells us about the number of electrons that are present in an atom. It also determines the atomic number of an element.

We are given:

Electronic configuration = $[Rn]7s^25f^{14}6d^4$

Radon is the noble gas having atomic number 86. It has 86 number of electrons.

Total number of electrons in the given element = (86 + 2 + 14 +4) = 106

Element having atomic number '106' is Seaborgium

Hence, the element having given configuration is Seaborgium.

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Which of the following groups in the periodic

Dimas [21]

Elements of Group 1 and group 2 in the periodic table contain elements so reactive that they are never found in the free state

Explanation:

The metals in group 1 of periodic table consisting of 'alkali metals' which include lithium, potassium, sodium, rubidium, Francium and caesium. They are highly reactive because they have low ionisation energy and larger radius. The group 2 metals consist of 'alkaline earth metals' which include calcium, strontium, barium, beryllium, radium and magnesium. These alkaline earth metal have +2 oxidation number, hence are highly reactive.

These both group metals are mostly reactive and so are never found in a free state. When they are exposed to air they would immediately react with oxygen. Hence, are stored in oils to avoid oxidation.

7 0

3 years ago

A certain solution of methylamine has a pOH of 6.8, while a solution of pyridine has a pOH of 6.0. Which solution has a greater

Liono4ka [1.6K]

Answer:

Pyridine solution has a greater concentration of hydroxide ions.

Explanation:

The pOH of the solution is defined as negative logarithm of hydroxide ion concentration in a solution.

$pOH=-\log [OH^-]$

Higher the value of pOH lessor will be the hydroxide ion concentration and higher the concentration of hydrogen ions in the solution .
Lower the value of pOH higher will be the hydroxide ion concentration and lower the concentration of hydrogen ions in the solution.

1) The pOH of the methylamine = 6.8

$6.8=-\log[OH^-]$