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3 years ago

Elements and compounds are two types of what

1 answer:

7 0

Elements and compounds are two types of substances ( I think). An element is any material made up of one type of atom- there could be multiples of this atom though for example oxygen which has a formula of 02. A compound is a substance made up of more than one type of atom for example H2O Hope this helped! :)

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An ion with an atomic number of 34 and 36 electrons has a __________ charge

Solnce55 [7]

<span>negative charge. The atomic number of 34 tells you immediately that the ion has 34 protons. Since it also has 36 electrons, it has 2 more electrons than needed to be neutral. So the ion will have a negative charge since electrons have a negative charge.</span>

5 0

2 years ago

Which of the following mixtures may be act as a buffer solution?

lions [1.4K]

Answer:

B) HF, NaF

Explanation:

A buffer solution is made up of a weak acid and its conjugate base.
In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF, and NaF would make a perfect buffer solution.
The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.

4 0

3 years ago

I need help solving this!

zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, $CH_{4}$ .

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol$

The given reaction equation is as follows.

$C + 2H_{2} \rightarrow CH_{4}$

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

$Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol$

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, $CH_{4}$ .

5 0

3 years ago

If 57.3 l of 0.497 m koh is required to completely neutralize 39.5 l of a CH3COOH solution. What is the molarity of the acetic a

bearhunter [10]

The molarity of the solution will be 0.72 m.

The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.

The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

Given data:

$V_{1} =57.3 L\\V_{2} = 39.5 L\\M_{1} = 0.497 m\\\\M_{2} = ?$

Molarity can be determined by the formula:

$M_{1} V_{1} = M_{2} V_{2}$

where, M is molarity and V is volume.

Put the value of given data in above equation.

57.3 × 0.497 m = M × 39.5 L

M = 0.72 m

Therefore, the molarity of the solution will be 0.72 m

To know more about molarity

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6 0

1 year ago

What is the chemical formula for sodium sulfate?

yan [13]

Hello!

When finding the chemical formula of a compound, we will need to find the charges of each element/bond.

Looking at our period table, sodium has a +1 charge, written as Na 1+, and sulfate has a charge of -2, and it is written as SO4 2-.

Now, we need to make the charges equivalent. To do this, we need to "criss-cross" the charges. This means that sodium will need to additional atoms to make the charges equal, and sulfate will need one.

Therefore, the chemical formula for sodium sulfate is: Na2SO4.

5 0

3 years ago