The net force on the block acting perpendicular to the incline is
∑ <em>F</em> = <em>n</em> - <em>w</em> cos(29.4°) = 0
where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.
The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.
Solve for <em>n</em> :
<em>n</em> = <em>m g</em> cos(29.4°)
<em>n</em> = (6 kg) (9.80 m/s²) cos(29.4°)
<em>n</em> ≈ 51.2 N
Explanation:
...domains are aligned which creates a magnetic field.
... are not always aligned so the resulting element had no apparent magentism
Speed is distance divided by time (s = d/t)
Answer:
7. free fall -- h. 9.8m/s^2
3. Velocity -- x. 60 km/hr west
6. Acceleration -- d. change in velocity/time
8. Centrifugal -- s. towards the centre
13. Work done --w. Force * displacement
5. Uniform circular motion --j. spin cycle in washer
18. Power -- r. kW an hour
7. g -- a. 10N
hope this helps
