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Slav-nsk [51]
4 years ago
13

Why is peer review important when publishing experimental results?

Chemistry
1 answer:
erastovalidia [21]4 years ago
7 0
When publishing experimental results, it is always advisable to have your peer review those results. This peer can confirm the results that you got and thus they will be more reliable.

Also, you will be sure that what what you are publishing is correctly presented as it is always good to have a fresh eya to double-check what is written.
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QuODUUII IU VI<br> 2 Points<br> What is molarity?
Julli [10]

Answer:

Molarity is similar to Concentration

Explanation:

Molarity (M) is the amount of solute in a solvent, similar to concentration.

5 0
4 years ago
Read 2 more answers
How many moles of MgS2O3 are in 201g of the compound?
Tamiku [17]
 <span>divide the 201g by the mol mass of the compound. Just add up the masses of the various element</span>
8 0
3 years ago
Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

6 0
3 years ago
All the bases are not alkali ​why
Vanyuwa [196]

Alkali are soluble bases, however not all bases are soluble in water, therefore not all bases are Alkali.

6 0
3 years ago
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Write 4.13X10^3 in decimal notation.
alukav5142 [94]

Answer:

4.13X10^3= 4130 in the expanded form

4 0
3 years ago
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