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pashok25 [27]
3 years ago
11

A ball is thrown straight up at an initial speed of 9.8m/s and, on returning to your hand, hits it moving downward at the same s

peed. If the whole trip took 2.0s, determine the ball’s (a) average acceleration and (b) average velocity.
Physics
1 answer:
likoan [24]3 years ago
3 0

Answer:

-9.8 m/s²

0 m/s

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-9.8 m/s − 9.8 m/s) / 2.0 s

a = -9.8 m/s²

Average velocity is the change in position over change in time.

v = Δx / Δt

v = (0 m − 0 m) / 2.0 s

v = 0 m/s

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Ballon volume of 3200ml of xenon gas is at a gauge pressure of 122kPa and a temperature of 27c. What is the volume when the ball
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Given:

The initial volume of the gas, V₁=3200 ml=3.2×10⁻³ m³

The initial pressure of the gas, P₁=122 kPa

The initial temperature of the gas, T₁=27 °C=300 K

The final temperature, T₂=65 °C=338 K

The final pressure, P₂=112 kPa

To find:

The final volume of xenon gas.

Explanation:

From the combined gas law,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Where V₂ is the volume after it is heated.

On rearranging the above equation,

V_2=\frac{T_2P_1V_1}{T_1P_2}

On substituting the known values,

\begin{gathered} V_2=\frac{338\times112\times10^3\times3.2\times10^{-3}}{300\times112\times10^3} \\ =3.61\text{ m}^3 \end{gathered}

Final answer:

The volume of the balloon when it is heated is 3.61 m³

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1 year ago
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