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Elden [556K]
3 years ago
11

The spacecraft Voyager was launched and continues traveling in space, even though it doesn't have an engine that pushes it forwa

rd. The fact that Voyager travels in space is an example of
Question 15 options:

Newton’s Second Law of Motion.


Newton’s First Law of Motion.


the Law of Conservation of Momentum.


Newton’s Third Law of Motion.
Physics
1 answer:
kkurt [141]3 years ago
3 0

Answer: 1st law of motion

Explanation:

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The answer is letter choice B...
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The Yerkes Primate Center has existed (or has been in existence) since the 1960s and has a focus in two major areas: Immunology
dybincka [34]

Answer:

Research towards increasing the understanding of progressive illnesses, such as Parkinson’s and Alzheimer’s diseases.

Explanation:

The Yerkes Primate center was established in 1930 by Robert Yerkes, in Orange Park, Florida. But was moved to its present location in Emory University.

The center has its focus on two major area of research, which are  Immunology and Vaccine, and research towards  increasing the understanding of progressive illnesses, such as Parkinson’s and Alzheimer’s diseases.

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A hockey puck is traveling to the left with a velocity of v=10 when it is struck by the hockey stick
Lera25 [3.4K]
We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
= ( 20 * 0.766 ) i + ( 20 * 0.64278 ) j = ( 15.32 i + 12.855 j ) m/s
Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
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| Δv | = √ ( 25.32² + 12.855²) = √806.35 = 28.4 m/s
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Answer: D ) 5.68 N-s. 
 
4 0
3 years ago
A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is
tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency = f = 562Hz

Speed of sound in air = v = 331m/s

The definition of wavelength is,

\lambda = \frac{v}{f}

Here,

v = Velocity

f = Frequency

Replacing,

\lambda = \frac{331m/s}{562Hz}

\lambda = 0.589m

Therefore the wavelength of that tone in air at standard conditions is 0.589m

3 0
3 years ago
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