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3 years ago

I'LL GIVE BRAINLY AGAIN <3

Chemistry

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

B) One way of solving this is to use dimensional analysis and cancel out grams to find volume.

A) density over mass is volume. Mass is 84.7 g and volume is 49.6 cm cubed

Explanation:

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Short Response

Natalija [7]

Answer:

6.)

7.) 134.4 g O₂

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ---> N₂ (g) + H₂O (g) + energy

Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen

Products: 2 nitrogen, 2 hydrogen, 1 oxygen

The balanced equation:

4 NH₃ (g) + 3 O₂ (g) ---> 2 N₂ (g) + 6 H₂O (g) + energy

Reactants: 4 nitrogen, 12 hydrogen, 6 oxygen

Products: 4 nitrogen, 12 hydrogen, 6 oxygen

To convert from moles to grams, you need to multiply the starting value (4.2 moles) by the molar mass (32.00 g/mol). The molar mass can serve as a conversion because it technically means there are 32.00 grams O₂ per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator).

4.2 moles O₂ 32.00 g
-------------------- x ---------------- = 134.4 g O₂
1 mole

8 0

2 years ago

Why can't liquids change volume but gases can

brilliants [131]

The Particles in the gas are to far apart from each other, so they do not have a volume nor shape.

8 0

3 years ago

5. Which contains more nitrogen: 60g of urea, (NH2)2CO, or 100g of ammonium sulphate, (NH4)2SO4

topjm [15]

Answer:

Urea contains more nitrogen

Explanation:

1 mole of Urea contains 2 moles of Nitrogen and 1 mole of ammonium sulfate contains, also, 2 moles of nitrogen.

60g of urea (Molar mass: 60g/mol) contains:

60g × (1mol / 60g) = 1 mole. As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 2.

100g of ammonium sulfate (Molar mass: 132g/mol) contains:

100g × (1mol / 132g) = 0.758 moles.

As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 0.758×2 = 1.516 moles.

That means, urea contains more nitrogen.

5 0

3 years ago

A catalyst will

scZoUnD [109]

Answer:

increase the chemical rate

7 0

3 years ago

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

6 0

3 years ago