D.Neither High- nor low-pressure systems lead to rain
Answer:
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
The purpose here is derive x(t) twice as follows:
Thus, the acceleration turns out 4.8 meters per squared seconds.
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B. heat is correct answer
Answer:
Explanation:
Let's assume that an object is launched straight upward in a gravitational field. Its initial kinetic energy is given by
(1)
where m is the mass and v is the initial speed.
As the object goes higher, its kinetic energy decreases and it is converted into gravitational potential energy, since the total mechanical energy (sum of kinetic and potential energy) must remain constant:
At the highest point of the trajectory, the speed of the object is zero (v=0), so the kinetic energy is also zero (K=0), which means that all the kinetic energy has been converted into potential energy:
(2)
where g is the gravitational acceleration and h is the maximum height of the object.
Due to conservation of energy, we can write that (1) and (2) are equal, so:
from which we can derive an expression for the maximum height reached by the object
Answer:
a= 1.59 m/s² : Magnitude of the acceleration
β = 65.22° (north of east) : Direction of the acceleration
Explanation:
Conceptual analysis
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
The acceleration is presented in the direction of the resultant force applied .
Calculation of the resultant forces (R)
R= 429.5 N
We apply the formula (1) to calculate the magnitude of the acceleration(a) :
∑F = m*a , m= 270 kg
R= m*a
429.5 =270*a
a= 1.59 m/s²
Calculation of the direction of the acceleration (β)
β = 65.22° (north of east)