Answer:
The vertical distance traveled is 3.18 m.
Explanation:
In order to find the vertical distance traveled by a body in free fall motion, starting from rest to a velocity of 7.9 m/s. For this purpose, we use Newton's third equation of motion,
2as = Vf² - Vi²
where,
a = g = 9.8 m/s²
s = vertical distance = Δy = ?
Vf = final velocity = 7.9 m/s
Vi = initial velocity = 0 m/s
Therefore,
2(9.8 m/s²)Δy = (7.9 m/s)² - (0 m/s)²
Δy = (7.9 m/s)²/(2)(9.8 m/s²)
<u>Δy = 3.18 m</u>
As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.
<h3>
What is angular momentum?</h3>
Angular momentum is defined as the quantity of rotation of a body, which is the product of mass, velocity and radius.
L = mvr
L = mωr²
where;
- m is mass of the object
- v is velocity
- r is radius
- ω is angular velocity
As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.
Learn more about angular momentum here: brainly.com/question/4126751
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When atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.
<h3>
How does atom combine?</h3>
Atoms can combine with each other through sharing of the electrons, donating the electrons etc. to make molecules.
When atoms combine by forming covalent bonds, the resulting collection of atoms is called a molecule. We can therefore say that a molecule is the simplest unit of a covalent compound.
Thus, when atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.
Learn more about combination of atoms here: brainly.com/question/5974633
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Refer to the figure shown below.
Let V = speed of the boat relative to the water
Given:
u = 1 km/h the speed of flowing water.
When traveling downstream from A to B, the actual speed of the boat is
V₁ = V + u = V + 1 km/h
When traveling upstream from B to A, the actual speed of the boat is
V₂ = V - u =V - 1 km/h
Because the distance Ab is 1 km, the time taken for the round trip is
t = (1 km)/(V+1 km/h) + (1 km)/(v-1 km/h)
= (V-1 + V+1)/(V² - 1)
= (2V)/(V² - 1)
The time for the round trip is 50 min = 5/6 h.
Therefore
(2V)/(V² - 1) = 5/6
5(V² - 1) = 12V
5V² - 12V - 5 = 0
Solve with the quadratic formula.
V = (1/10)*[12 +/- √(144 + 100)] = 2.762 or -0.362 km/h
Ignore negative speed, so that
V = 2.762 k/h
Answer:
The speed of the boat relative to the water is
2.76 km/h (nearest hundredth)