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3 years ago

What is the mass in kilograms of a copper pipe that weighs 12.5 pounds? (1 lb = 453.6 g)?

1 answer:

7 0

To solve this problem we will apply the concepts of conversion. We will simply carry the value of pounds to kilograms, so from the statement we have the equivalent:

$1lb = 0.453592kg$

Now if 1 lb is equivalent to that value, 12.5 lb would be

$m = 12.5lb (\frac{0.453592kg }{1lb}) \rightarrow$ Note that the values are available in this order and the units are also canceled and the kilograms are maintained.

$m = 5.61kg$

$\therefore 12.5 ft \text{ is equal to } 5.61kg$

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2 years ago

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Cual es la velocidad de un atleta que se tarda 50 segundos en recorrer una pista de 400 metros

dedylja [7]

Answer:

v = 8 [m/s]

Explanation:

Debemos determinar la velocidad promedio, esta velocidad se define como la relacion entre la distancia recorrida sobre un determinado tiempo.

De esta manera tenemos la siguiente expresion:

v = x/t

donde:

v = velocidad [m/s]

x = distancia = 400 [m]

t = tiempo = 50 [s]

v = 400/50

v = 8 [m/s]

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2 years ago

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

dalvyx [7]

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

$a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2$

The centripetal acceleration is directed inwards.

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2 years ago

A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile

docker41 [41]

Answer:

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity = 750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum = $0.005 \times 750$