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2 years ago

Adam takes a bus from school to his house. If Adam lives 20 km from

Physics

2 answers:

katrin2010 [14]2 years ago

7 0

Answer:

Since there is already an answer up, i am going to go in depth and show how that answer was found.

Explanation:

We know that S=d/t, where s=speed, d=distance, and t=time, we are given 2 variables which are the distance of 20km and the time of 10 minutes.

We can plug that into our equation and we get:

S=20km/10min

simplify,

S=2km/1min

thus, the average velocity would be 2 km/min

SIZIF [17.4K]2 years ago

5 0

2.0 km/min is the answer

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A cylindrical container with a cross-sectional area of 66.2 cm2 holds a fluid of density 856 kg/m3 . At the bottom of the contai

Ugo [173]

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a) Let us assume the depth be h

As we know that

$Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h$

After solving this,

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

Given that

height of the extra fluid is

$h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}$

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

$Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000$

Pb' = 122 KPa

3 0

3 years ago

In a chemical equation, where do the reactants appear?

Bess [88]

Answer: A chemical equation describes a chemical reaction. Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

8 0

3 years ago

Consider two adjacent states, S1 and S2, that wish to control particulate emissions from power plants and cement plants; New Jer

natka813 [3]

Answer:

a. 7500

b. Yes

c. 2500

d. 7500

Explanation:

Please see attachment

7 0

3 years ago

The mass of the container holding this table salt is 3G. What is the mass of the table salt

GenaCL600 [577]

20 i think

Good Luck!

5 0

3 years ago

What is the minimum speed must a salmon jumping at an angle of 35.2 leave the water in m/s?

yuradex [85]

Height of the waterfall is 0.449 m

its horizontal distance will be 2.1 m

now let say his speed is v with which he jumped out so here the two components of his velocity will be

$v_x = vcos35.2 = 0.817 v$

$v_y = vsin35.2 = 0.576 v$

here the acceleration due to gravity is 9.81 m/s^2 downwards

now we can find the time to reach the other end by y direction displacement equation

$\Delta y = v_y * t + \frac{1}{2} at^2$

$-0.449 = 0.576 * v *t - \frac{1}{2}*9.81 * t^2$

also from x direction we can say

$\Delta x = v_x * t$

$2.1 = 0.817 v* t$

now we have

$v* t = 2.57$

we will plug in this value into first equation

$- 0.449 = 0.576 * 2.57 - 4.905 * t^2$

$1.93 = 4.905 * t^2$

$t = 0.63 s$

now as we know that

$v* t = 2.57$

t = 0.63 s

$v = \frac{2.57}{0.63}$

$v = 4.1 m/s$

so his minimum speed of jump is 4.1 m/s

8 0

3 years ago