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olga_2 [115]
3 years ago
9

Is baking soda less, or more denser than water?

Chemistry
2 answers:
Shkiper50 [21]3 years ago
6 0
More dense than water
34kurt3 years ago
3 0

Answer:

baking powder is more dense than water

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The reaction 2X →products is a second-order reaction, and the rate constant is 8.8 × 10−3 1/M·s. If the initial concentration of
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Answer is: A) 124 s.
c₀ = 3 mol/L.
c₁ = 0,700 mol/L.
k = 8,8·10⁻³ 1/M·s.
Integrated second order rate law is: 1/c₁ = 1/c₀ + k·t.
k·t = 1/0,700 - 1/3.
0,0088·t = 1,095.
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t = 124 s.
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c</span>₁ - <span> concentration at a particular time.
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Zinc + Hydrochloric Acid → Zinc Chloride and Hydrogen Gas
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Explanation:

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Write the oxidation and reduction half reactions;
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Answer:

a)

Fe^{2+}⇒Fe^{3+}+e^-

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b)

Mg⇒Mg^{2+}+2e^-

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Explanation:

A)

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

Fe^{2+}⇒Fe^{3+}+e^-

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

Br_2+2e^-⇒2Br^-

b)

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

Mg⇒Mg^{2+}+2e^-

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Cr^{3+}+e^-⇒Cr^{3+}

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4 years ago
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