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lina2011 [118]
2 years ago
7

HELP PLSSSSSSSSSSSSSSSSSSS

Chemistry
2 answers:
sdas [7]2 years ago
5 0

Answer:

1: marine

2:rainforest

Temperate deciduous forest

taiga

tundra

desert

Explanation:

grigory [225]2 years ago
5 0
I agree with what the other person said
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Aleksandr [31]
The biggest source of vitamin D is the sun.
5 0
3 years ago
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You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
san4es73 [151]

Answer:

4- A material that transfers heat energy more easily than another material will experience a greater rate of thermal energy loss than an object that does not transfer heat energy easily.

Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

On a cold day, a material that transfers thermal energy more easily will loose thermal energy faster than an object that does not transfer thermal energy. The rate of heat transfer of a body determines its rate of loss of thermal energy.

6 0
3 years ago
For the following Bronsted acid-base reaction, complete the reaction, identify the acid, base, conjugate
madam [21]

Answer:

algun moderador puede acabar a este otro este me borró respuesta que no debió borrar

7 0
2 years ago
The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
If I have 8 moles of Iron atoms in the products, how many moles of Iron atoms did I start with?
Vika [28.1K]

Answer: You started with 8

Explanation: the amount of products is equal to the amount of reactants

6 0
3 years ago
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