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4 years ago

BTW THIS A 2 QUESTION TEST THERE WILL BE 2 THINGS TO ANSWER

1 answer:

8 0

William finds a piece of pure iron in his garden. After a few days, the iron begins to rust. What are the two types of substances involved in the rusting process of iron?

Iron is (B) an element.

with one kind of atom that combines with oxygen from the air to form rust (iron oxide). Rust contains two types of atoms, which means it is

(A) a compound

Hope this helps. Have a nice day.

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PLEASE HELPP!!!!!!!!!

Mama L [17]

I just wannasay i love your cat

8 0

3 years ago

An object is thrown vertically and has a speed of 25 m/s when it reaches 1/4 of its maximum height above the ground (assume it s

Crazy boy [7]

Answer:

$v_{i} =28.86\frac{ft}{s}$

Explanation:

Conceptual analysis

We apply the kinematic formula for an object that moves vertically upwards:

$(v_{f} )^{2} =(v_{i} )^{2} -2*g*y$

Where:

$v_{f}$ : final speed in ft/s

$v_{i}$ : initial speed in ft/s

g: acceleration due to gravity in ft/s²

y: vertical position at any time in ft

Known data

For $v_{f} = 25\frac{ft}{s}$ , $y=\frac{1}{4} h$ ; where h is the maximum height

for y=h, $v_{f} =0$

Problem development

We replace $v_{f} = 25\frac{ft}{s}$ , $y=\frac{1}{4} h (ft)$ in the formula (1),

[ $25^{2} =(v_{i} )^{2} -2*g*\frac{h}{4}$ Equation (1)

in maximum height(h): $v_{f} =0$ , Then we replace in formula (1):

$0=(v_{i} )^{2} - 2*g*h$

$2*g*h=(v_{i} )^{2}$

$h=\frac{(v_{i})^{2} }{2g}$ Equation(2)

We replace (h) of Equation(2) in the Equation (1) :

$25^{2} =(v_{i} )^{2} -2g\frac{\frac{(v_{i})^{2} }{2g} }{4}$

$25^{2} =(v_{i} )^{2} -\frac{(v_{i})^{2} }{4}$

$25^{2} =\frac{3}{4} (v_{i} )^{2}$

$v_{i} =\sqrt{\frac{25^{2}*4 }{3} }$

$v_{i} =28.86\frac{ft}{s}$

7 0

4 years ago

Which of the statements below is true?

Cloud [144]

Answer:

An object’s weight is proportional to its mass.

8 0

3 years ago

A string is stretched to a length of 376 cm and

sergey [27]

Answer: 53.09Hz

Explanation:

The fundamental frequency of an ideal taut string is:

Fn= n/2L(√T/μ)

Where:

F= frequency per second (Hz)

T= Tension of the string (cm/s sqr)

L= Length of the string (cm)

μ= Linear density or mass per unit length of the string in cm/gm

√T/μ= square root of T divided by μ

It is important to note:

Note: Typically, tension would be in newtons, length in meters and linear density in kg/m, but those units are inconvenient for calculations with strings. Here, the smaller units are used.

F1= 1/2(376cm)(0.01/1) × (√574/(0.036g/cm)(0.1kg/m÷1g/cm)

F1= 0.1329 × 399.30

= 53.09Hz

7 0

3 years ago

Egg A is dropped from a height of 1m onto the floor. Egg B is dropped from a height of 1m into a bucket of water. Which statemen

NeTakaya

Answer:

maybe it's because a bucket of water has more density than egg B

3 0

3 years ago

Read 2 more answers