Answer:
Horizontal acceleration is 0 in a projectile motion
Explanation:
first we have to find the horizontal velocity
15cos40 = 11.49ms^-1
and then use the following equation to find the distance
None of the choices is correct.
== The Earth's radius is 6,371 km. That's how far you are from the center of the Earth when you're on the ground.
== The acceleration of gravity on the ground is 9.8 m/s² .
== The acceleration of gravity varies inversely as the square of the distance from the center of the Earth. So, at 7,200 km from the center, it's
(9.8 m/s²) · (6371km/7200km)² .
Stuffing this through your cakulator, you'll get <em>7.67 m/s²</em> .
<h3>Answer</h3>
6.6 N pointing to the right
<h3>Explanation</h3>
Given that,
two forces acting of magnitude 3.6N
angle between them = 48°
To find,
the third force that will cause the object to be in equilibrium
<h3>1)</h3>
Find the vertical and horizontal components of the two forces
vertical force1 = sin(24)(3.6)
vertical force2= -sin(24)(3.6)
<em>(negative sign since it is acting on opposite direction)</em>
vertical force3 = sin(24)(3.6) - sin(24)(3.6)
= 0
<h3>2)</h3>
horizontal force1 = cos(24)(3.6)
horizontal force2= cos(24)(3.6)
horizontal force3 = cos(24)(3.6) + cos(24)(3.6)
= 2(cos(24)(3.6))
= 6.5775 N
≈ 6.6 N
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I would say vibrations, but is there choices?
