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Tomtit [17]
4 years ago
6

What force is required to accelerated a body with a mass of 15 kilograms at a rate of 8 m/s2

Physics
1 answer:
rjkz [21]4 years ago
7 0

Force  =  (mass) · (acceleration)

           = (15 kg) · (8 m/s²)

           =  120 kg-m/s²  =  120 newtons
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A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is
mihalych1998 [28]

Answer:

a) v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

b) \theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

c)t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

d) Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that v_y = 2 m/s represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is V_x= 4.8 m/s

And we want to find the velocity of the motord board relative to the Earth v_m

And we can find this velocity from the Pythagorean Theorem.

v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

Part b

We can find the direction with the following formula:

\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

D = Vt

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

Part d

For this case we can use the same definition but now using the y compnent we have:

Y = v_y t

And replacing we got:

Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

7 0
3 years ago
Ok plz answer and tell me how to do it
kirza4 [7]
Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.
4 0
3 years ago
What is the static friction force and kinetic friction for the image
jasenka [17]

According to the plot, static friction force has a maximum magnitude of around 3.0 N, and kinetic friction has a magnitude of about 1.5 N.

The plot appears to be telling you the force required to get the yellow block moving along the table. If one applies less than 3.0 N of force, the block remains motionless. But as soon as it starts to slide, one need only apply 1.5 N of force to keep it moving (presumably at a constant speed).

8 0
3 years ago
Which type of reaction is shown in this energy diagram?
valentinak56 [21]

Answer:

Option C

Explanation:

The graph shows endothermic reaction because the reactants are lower in energy and the products are higher is energy. Endothermic reactions absorb energy having products with higher energy.

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4 years ago
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Un coche de unos 500 kg viaja a 90 km/h. Percibe un obstáculo y debe frenar a tope. Por las marcas del suelo se sabe que el espa
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Answer:

THERE'S A GIRL WHO WILL STEAL YOUR INFO, PLZ DON"T PRESS THE LINK IF SHE ASKS YOU TOO!!!!!

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