All categories

3 years ago

What is the oxidation number of each atom in sodium hydrogen carbonate

Chemistry

1 answer:

Sati [7]3 years ago

8 0

Answer:

Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are

Na = +1

H = +1

C = +4

O = -2

Explanation:

Let's pick the first atom

NaHCO3

find oxidation number of Na

Na + 1 +4 + 3(-2) = 0( because there is no charge)

Na + 5 - 6 = 0

Na = 6 -5

Na = +1

Always put the sign

Find the oxidation number of H in NaHCO3

+1 + H + 4 + 3(-2) = 0.

H + 1 + 4 + 3(-2) = 0

H + 5 -6 = 0

H = 6 -5

H = +1

Find the oxidation number of C In NaHCO3

+1 +1 +C + 3(-2) = 0

C + 1+1-6 = 0

C +2 - 6= 0

C = 6 -2

C = +4

Find the oxidation number of O in NaHCO3

+1 + 1 + 4 + 3(O) = 0

6 + 3 (O) = 0

3(O) = -6

Divide through by 3 to get O

3(O) / 3 = -6 / 3

O = -6/3

O = -2

You might be interested in

Students in a lab used a hot plate to boil water. Which of the following illustrations best represents the change in the movemen

Digiron [165]

The second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.

<u>Explanation:</u>

The second option perfectly represents the boiling of water. As when the temperature is increased, the water molecules gain energy to move faster, thus their kinetic energy of the atoms will be more. This will lead to more freely movement of all the atoms of the water.

And as boiling leads to transformation from liquid state to gaseous state, so the increase in the distance between atoms and molecules occurs in the gaseous state. Thus, the second illustration is best suitable for representing the boiling of water.

As on increasing temperature of the water, the distance between the molecules is increasing in the second illustration while the other illustration shows the decrease in the distance between the molecules. So, the second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.

6 0

3 years ago

Increasing the amount of water in which the sugar is dissolved will increase the frequency of collisions between the sucrose mol

Sonja [21]

Answer: The given statement is true.

Explanation:

When we increase the amount of solvent which is water in this case then it means there will occur an increase in the molecules. Hence, there will be more number of collisions to take place with increase in number of molecules.

Therefore, more is the amount of interaction taking place between the molecules of a solution more will be its rate of hydrolysis.

Thus, we can conclude that the statement increasing the amount of water in which the sugar is dissolved will increase the frequency of collisions between the sucrose molecules and the water molecules resulting in an increase in the rate of hydrolysis, is true.

8 0

3 years ago

A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 ml of 0.106 m naoh. calculat

Jet001 [13]

Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.

6 0

3 years ago

4) express 55mg in kilograms

artcher [175]

55 mg =

.00005500000 kg

6 0

3 years ago

When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M = 163 m/z) is formed.

DanielleElmas [232]

Answer:

As the molecular mass of given amine is 163 g/mol (a odd number) it means that this compound contains a odd number of Nitrogen atoms. We will first apply Rule of Thirteen to get the molecular formula.

Rule of Thirteen:

First divide the parent peak value by 13 as,

= 163 ÷ 13

= 12.53

Now, multiply 13 by 12,

= 13 × 12 (here, 12 specifies number of carbon atoms)

= 156

Now subtract 156 from 163,

= 163 - 156

= 7

Add 7 into 12,

= 7 + 12

= 19 (hydrogen atoms)

So, the rough formula we have is,

C₁₂H₁₉

Now, add one Nitrogen atom to above formula and subtract one Carbon and 2 Hydrogen atoms as these numbers are equal to atomic mass of Nitrogen atom as,

C₁₂H₁₉ -------N--------> C₁₁H₁₇N

Also, as shown in ¹³C-NMR there is one peak around 180 ppm and the peak at 1661 cm⁻¹ in IR spectrum is characteristic to carbonyl group hence, we will add one oxygen atom to the chemical formula accordingly. i.e.

C₁₁H₁₇N -------O--------> C₁₀H₁₃NO

Molecular Formula: C₁₀H₁₃NO

Also,

In NMR the the four peaks around 120 ppm are assigned to a mono substituted benzene ring.

The absence of IR peak above 3200 cm⁻³ also confirms that the amine is tertiary in nature and there is no hydrogen attached to the nitrogen atom.

It can be observed that the peaks in upfield are duplicating. This can be due to the presence of rotamers of said compound.

The most plausible structure for given data is shown below, and the resonance structure along with rotamers are also shown.

6 0

3 years ago